April 27, 2015
Target
To solve an equation for a variable.
Question of the Day
What are we doing today?
Solve.
1. s = 3f – 24 for f
2. V = πr2h for h
10.5 – Solving for a Variable
- Correct HW – Practice B
- Lecture and Vocabulary (Pg. 519)
- HW – Solving and Graphing Practice
Due: Tomorrow
April 28, 2015
Target
To solve an equation for a variable.
Question of the Day
What are we doing today?
Solve for y.
1. x – 4y = 15
2. 4x – 2y = 14
10.5 – Solving for a Variable
- Correct HW – Solving and Graphing
- Lecture and Vocabulary (Pg. 545) –
11.2!
- HW – Finish yesterdays work
Due: Tomorrow
April 29, 2015
Target
To solve an equation for a variable.
Question of the Day
What is slope? - DEFINE
What are we doing today?
10.5 – Solving for a Variable
- Correct HW – Solving and Graphing
- Lecture and Vocabulary (Pg. 545) –
11.2!
- HW – Finish yesterdays work
Due: Tomorrow
April 30, 2015
Target
To graph slope-intercept form linear equations
Question of the Day
What are we doing today?
Identify the slope and y-intercept.
Slope Intercept Form
- Solving For and Graphing
- Graph last night’s HW
- HW – Graphing S-I Form (again)
1.
2.
3.
y = 3x – 5
y = (-2/3)x + 1
y=x
Due: Monday
May 1, 2015
Target
Question of the Day
What are we doing today?
Due: