Physics 200 Class #13 Notes October 19, 2005 Reading Assignment Text: Chapter 6 pp. 141-160 Review of: Electric Force - F (newtons, N) Potential Energy - PE (joules, J) Electric Field - E (newtons/coulomb, N/C) "Electric Potential" - ""(volts, V) You know that the electric field relates to the electric force through the equation E=F/q, but how do force, electric field, potential energy, and "electric potential" relate? kQq kQ (in units of newtons, N) electric field E = 2 (newtons/coulomb, N/C) 2 r r kQq kQ Potential Energy PE = (joules, J) "electric potential" = (volts, V) r r NOTE: "electric potential" and potential energy are different things. You can think of electric potential as the pressure pushing the electrons along - like pressure in a hose pushing water along. If you have high pressure, you can have a spark across a large distance, if you have low pressure you can only have a spark across a short distance. electric force F = definitions in terms of Energy: Power (Energy/time) Intensity or brightness (Power/area) How bright are blackbody radiators - depends on temperature, and distance from object watts 5.67 x 108 2 4 ) (Power radiated R: R T 4 m K Much hotter stars than our sun look much dimmer. Why? Phy 200 Fall 2005 Class_13 Page 1 of 5 Tonight, we review the Photoelectric Effect, discuss Compton Scattering Chapter 6 The Photon Is the wave theory of light enough to describe all phenomena in which it participates? 6.2 The photoelectric Effect Einstein and the Photoelectric Effect 1. Collector positive: current flows 2. Collector negative: Current stops at some unique value Major Problem with Wave Model: There is no time delay between the light turning on and the ejection of photoelectrons! Classical theory predicts time delays of hours while the energy from a wave builds up on the electron. Recall from last time: Classroom demonstration of Photoelectric effect! Key Points: No time lag between turning on light and photocurrent. Each frequency has a unique stopping voltage. Increasing the Intensity of the light does not change the stopping voltage There is a threshold frequency below which there is no effect. The experimental facts are summarized by plotting stopping energy (voltage) versus frequency. Typical curves are shown in the next figure. Phy 200 Fall 2005 Class_13 Page 2 of 5 Interpretation: 1) The stopping voltage is a measure of the maximum kinetic energy of the ejected electrons. 2) The kinetic energy of the electrons is directly proportional to the frequency. 3) The threshold frequency indicates that the incident light must have a minimum energy to eject electrons. Einstein’s Interpretation: The light is quantized (photon) and has energy directly proportional to its frequency! Maximum energy of slope of a constant that depends f electron after escape graph line on the material KEmax hf W eVS hf W VS h W f e e or VS h h f f threshold e e W is the (Work Function): Minimum energy needed to remove electron from surface. This is a unique value for each metal. A new energy unit: The electron volt If we measure the stopping voltage in volts, we convert to joules by multiplying by the charge on the electron. One volt is equal to one joule/coulomb. The joule is an inconvenient unit to use in atomic physics. We usually specify the wavelength rather than the frequency: hc KEmax hf W W KEmax 1240eVnm W Example :Suppose =500nm and W=1.2eV 1240eVnm KEmax 1.2eV 2.48 1.2 1.28eV 500nm It would take 1.28 volts to stop the electrons. Phy 200 Fall 2005 Class_13 Page 3 of 5 6.3 The Compton Effect Quick review of momentum: mv The discovery of x-rays and their interaction with matter gives further evidence for the photon picture of light and also allows us to confirm that photons carry linear momentum. The scattering of x-rays from electrons allows us to determine the momentum of the photon. The “picture” of Compton Scattering (Compton Effect) is shown below. Production of X-rays: High speed electrons are shot into a metal and are rapidly accelerated (decelerated). Accelerating charges produce radiation. We apply Conservation of energy and conservation of momentum: Conservation of energy: energy of photon before + kinetic energy of electron before = energy of photon after + kinetic energy of electron after hfbefore zero hf after (kinetic energy of recoiling electron) So when the photon scatters, it loses energy and gives this energy to the electron. This means that it changes frequency (and wavelength) when it scatters. For example, green light hitting an electron may scatter off as red light, which has lower energy. Conservation of linear momentum: The calculation is a bit more complicated here, but analysis shows that the linear momentum of the photon can be written as follows: hf ( Momentum of photon) c or h ( Momentum of photon) So remember - photons have energy, and have momentum. They can push things around, like kicking electrons off of atoms. Phy 200 Fall 2005 Class_13 Page 4 of 5 Questions from Chapter 6 (p. 160) 1. A certain metal surface ejects electrons when illuminated with green light but none when struck by yellow light. Do you expect that electrons will be able to escape when the surface is illuminated (a) by red light? (b) by blue light? Explain your reasoning. 2. A good mirror reflects about 80 per cent of the light energy that strikes it. How could you distinguish experimentally between the following two possibilities: (a) 20 per cent of the photons are not reflected; (b) all the photons are reflected but each with 20 per cent less energy? 3. If an electron in metallic cesium absorbs a photon of red light (specifically, λ = 6.6 x 10-7 meters in vacuum), all the energy is used up in escaping from the attractive forces in the metal. There is no energy left over after the electron has gotten out (just barely). Suppose blue-green light (with λ = 5 x 10-7 meters) is used. What percentage of the photon's energy does the electron retain after it has escaped from the metal? (Recall that a photon's energy is determined by the frequency of the light. You can, however, readily convert wavelength information into frequency information. If you do some algebra, you will find that Planck's constant cancels out in the final answer. That will save you some nasty multiplying - and you will see things more clearly.) 4. Some photographic materials can be handled safely in red light but are spoiled instantly when white light is turned on. How might you account for this? 5. More about the photoelectric effect. The text never addressed the question of why some electrons have less energy after escape than others. Suppose zinc is illuminated with ultraviolet light of a single frequency, for example, f =1.5 threshold. Why might some electrons emerge with less energy than "maximum energy of electron after escape"? Phy 200 Fall 2005 Class_13 Page 5 of 5