1
ANSC 221
HOMEWORK 5
NAME -------------------------RATION BALANCING--SWINE TYPE
2 BASAL FEEDS AND MINERALS
---ANSWERS--FIXED AMOUNT OF Oats
BALANCE 100 POUNDS OF A RATION FOR SWINE TO CONTAIN
12.1 PERCENT PROTEIN.
MAKE THE RATION CONTAIN 5 PERCENT Oats AND USE CORN AND SOYBEAN MEAL TO SUPPLY
THE NEEDED AMOUNT OF ADDITIONAL PROTEIN.
LEAVE
3 PERCENT OF THE RATION FREE FOR VITAMINS, MINERALS, ETC.
BALANCE THE RATION TO CONTAIN .6 PERCENT CALCIUM AND .5 PERCENT PHOSPHORUS.
USE THE FOLLOWING INGREDIENT COMPOSITION (values are in percent)
Make it contain: 2 lbs/Ton of Trace Mineral premix
6 lbs/Ton of Vitamin premix
0.25% salt
250 PPM Copper from Copper Sulfate
1 lb per Ton of Selenium premix
80 Grams per Ton Tylosin
After balancing the ration, CALCULATE the percent LYSINE.
PROTEIN,
---------CORN
7.5
Oats
11
SOYBEAN MEAL
44.1
DICALCIUM PHOSPHATE
0
LIMESTONE
0
Tylan-10 contains 10 grams Tylosin/lb.
CuSO4-5H20 contains 25 percent copper.
CALCIUM,
---------.02
.10
.25
24.0
38
PLACE YOUR ANSWERS HERE:
Percent
TON
CORN
Oats
SOYBEAN MEAL
DICAL
LIMESTONE
SALT
TM Premix
Se PREMIX
VIT Premix
TYLAN-10
CU-SULFATE
OTHER
TOTAL
79.3
1586
5
100
12.7
253.9999
.9288108
18.57622
.8538827
17.07765
0.25
5
0.10
2
0.05
1
0.30
6
0.40
8
0.10
2
1.730645E-02
----------100
2000
PERCENT LYSINE IN RATION =
.6045799
.3461289
PHOSPHORUS,
---------.29
.44
.60
18.5
0
ANSWERS:
1
ANSC 221, Homework 5
ALGEBRAIC SOLUTION:
PEARSON SQUARE SOLUTION:
(100)( .121 ) = ( .075 )(X) + ( .11 )( 5 ) + (100- 3 - 5 -X)( .441 )
PROTEIN
CORN
Oats
SBM
12.1
= .075 X + .55
12.1
= .075 X + .55
12.1 - 40.572 - .55
= .075
-29.022
=
-.366 X
79.3
= X
12.7
=
92
( 5 )
+ ( 92 -X)( .441 )
+ 40.572 - .441 X
X - .441 X
( .11 ) =
STEP 2: (100 lbs) ( .121 ) =
12.1 - .55 = 11.55
STEP 3: 100- 5 - 3 = 92
11.55 / 92 =
- X
STEP 4:
---------- 31.5
:
:
: 12.6
:
:
:
44.1 ---------5.1
--------36.6
CORN = 79.3
Oats = 5
SBM = 12.7
7.5
MINERALS
--
.6 PERCENT CA
AND
.55
(100-AMT Oats-AMT EMPTY)
12.6
31.5
5.1
/
/
36.6
36.6
.5 PERCENT P
P IN GRAIN = (.0029)( 79.3 ) + (.0044)( 5 ) + (.006)( 12.7 ) =
CORN
Oats
SBM
.22997
+
.022
+
7.619999E-02
=
P STILL NEEDED = .5 - .32817 = .17183
AMT DICAL TO USE = .17183 / .185 = .9288108
CA IN GRAIN + DICAL = (.0002)( 79.3 ) + (.0010)( 5 ) + (.0025)( 12.7 ) + (.24)( .9288108 ) =
.01586
+
.005
+
3.174999E-02
+
.2229146
CA STILL NEEDED = .6 - .2755246 = .3244754
LIMESTONE TO USE TO GET .3244754 LBS CA = .3244754 / .38 =
TM Premix: 2 LBS/TON = 1 Lb/1000 = .5 lb/100 = .5%
Se Premix: 1 LB/TON = .5 lb/1000 = .05 lb/100 = .05%
Vit Premix: 6 LB/TON = 3 lb/1000 = .3 lb/100 = .3%
TYLAN-10: 80 g/ton = 40 g/1000 lb = 4 g/100 lb coming from
a compound with 10 g/lb of the tylan we want.
Therefore 4 g = X (10 g/lb) or 4/10 = .4 lbs TYLAN-10
CuSO4: 250 ppm = .025% Cu ; compound is 25% Cu so
.025 lb = X (.25) , or add .1 lb CuSO4 per 100 lbs feed.
OTHER should be calculated by subtracting all feeds from 100.0
.8538827
12.1
.2755246
.32817
x
x
92
92
=
=
79.3
12.7
2
ANSC 221
HOMEWORK 5
NAME -------------------------RATION BALANCING--SWINE TYPE
2 BASAL FEEDS AND MINERALS
---ANSWERS--FIXED AMOUNT OF Oats
BALANCE 100 POUNDS OF A RATION FOR SWINE TO CONTAIN
17.6 PERCENT PROTEIN.
MAKE THE RATION CONTAIN 9 PERCENT Oats AND USE CORN AND SOYBEAN MEAL TO SUPPLY
THE NEEDED AMOUNT OF ADDITIONAL PROTEIN.
LEAVE
3 PERCENT OF THE RATION FREE FOR VITAMINS, MINERALS, ETC.
BALANCE THE RATION TO CONTAIN .6 PERCENT CALCIUM AND .5 PERCENT PHOSPHORUS.
USE THE FOLLOWING INGREDIENT COMPOSITION (values are in percent)
Make it contain: 2 lbs/Ton of Trace Mineral premix
6 lbs/Ton of Vitamin premix
0.25% salt
250 PPM Copper from Copper Sulfate
1 lb per Ton of Selenium premix
80 Grams per Ton Tylosin
After balancing the ration, CALCULATE the percent LYSINE.
PROTEIN,
---------CORN
8.3
Oats
12.1
SOYBEAN MEAL
45.7
DICALCIUM PHOSPHATE
0
LIMESTONE
0
Tylan-10 contains 10 grams Tylosin/lb.
CuSO4-5H20 contains 25 percent copper.
PLACE YOUR ANSWERS HERE:
Percent
CORN
Oats
SOYBEAN MEAL
DICAL
LIMESTONE
SALT
TM Premix
Se PREMIX
VIT Premix
TYLAN-10
CU-SULFATE
OTHER
TOTAL
63.4
9
24.6
.696973
.9198592
0.25
0.10
0.05
0.30
0.40
0.10
.1831677
------
100
PERCENT LYSINE IN RATION =
TON
1268
180
492
13.93946
18.39718
5
2
1
6
8
2
3.663354
-----2000
.94794
CALCIUM,
---------.02
.10
.25
24.0
38
PHOSPHORUS,
---------.29
.44
.60
18.5
0
ANSWERS:
2
ANSC 221, Homework 5
ALGEBRAIC SOLUTION:
PEARSON SQUARE SOLUTION:
(100)( .176 ) = ( .083 )(X) + ( .121 )( 9 ) + (100- 3 - 9 -X)( .457 )
PROTEIN
CORN
Oats
SBM
17.6
= .083 X + 1.089
17.6
= .083 X + 1.089
17.6 - 40.216 - 1.089
= .083
-23.705
=
-.374 X
63.4
= X
24.6
=
88
( 9 )
+ ( 88 -X)( .457 )
+ 40.216 - .457 X
X - .457 X
( .121 ) =
STEP 2: (100 lbs) ( .176 ) = 17.6
17.6 - 1.089 = 16.511
STEP 3: 100- 9 - 3 = 88
(100-AMT Oats-AMT EMPTY)
16.511 / 88 = 18.8
- X
STEP 4:
---------- 26.9
:
:
: 18.8
:
:
:
45.7 ---------10.5
--------37.4
CORN = 63.4
Oats = 9
SBM = 24.6
8.3
MINERALS
--
.6 PERCENT CA
AND
1.089
26.9
/
37.4
x
88
=
63.4
10.5
/
37.4
x
88
=
24.6
.5 PERCENT P
P IN GRAIN = (.0029)( 63.4 ) + (.0044)( 9 ) + (.006)( 24.6 ) =
CORN
Oats
SBM
.18386
+
.0396
+
.1476
=
.37106
P STILL NEEDED = .5 - .37106 = .12894
AMT DICAL TO USE = .12894 / .185 = .696973
CA IN GRAIN + DICAL = (.0002)( 63.4 ) + (.0010)( 9 ) + (.0025)( 24.6 ) + (.24)( .696973 ) = .2504535
.01268
+
9.000001E-03
+
6.149999E-02
+
.1672735
CA STILL NEEDED = .6 - .2504535 = .3495465
LIMESTONE TO USE TO GET .3495465 LBS CA = .3495465 / .38 =
TM Premix: 2 LBS/TON = 1 Lb/1000 = .5 lb/100 = .5%
Se Premix: 1 LB/TON = .5 lb/1000 = .05 lb/100 = .05%
Vit Premix: 6 LB/TON = 3 lb/1000 = .3 lb/100 = .3%
TYLAN-10: 80 g/ton = 40 g/1000 lb = 4 g/100 lb coming from
a compound with 10 g/lb of the tylan we want.
Therefore 4 g = X (10 g/lb) or 4/10 = .4 lbs TYLAN-10
CuSO4: 250 ppm = .025% Cu ; compound is 25% Cu so
.025 lb = X (.25) , or add .1 lb CuSO4 per 100 lbs feed.
OTHER should be calculated by subtracting all feeds from 100.0
.9198592
3
ANSC 221
HOMEWORK 5
NAME -------------------------RATION BALANCING--SWINE TYPE
2 BASAL FEEDS AND MINERALS
---ANSWERS--FIXED AMOUNT OF Oats
BALANCE 100 POUNDS OF A RATION FOR SWINE TO CONTAIN
18.1 PERCENT PROTEIN.
MAKE THE RATION CONTAIN 15 PERCENT Oats AND USE CORN AND SOYBEAN MEAL TO SUPPLY
THE NEEDED AMOUNT OF ADDITIONAL PROTEIN.
LEAVE
3 PERCENT OF THE RATION FREE FOR VITAMINS, MINERALS, ETC.
BALANCE THE RATION TO CONTAIN .6 PERCENT CALCIUM AND .5 PERCENT PHOSPHORUS.
USE THE FOLLOWING INGREDIENT COMPOSITION (values are in percent)
Make it contain: 2 lbs/Ton of Trace Mineral premix
6 lbs/Ton of Vitamin premix
0.25% salt
250 PPM Copper from Copper Sulfate
1 lb per Ton of Selenium premix
80 Grams per Ton Tylosin
After balancing the ration, CALCULATE the percent LYSINE.
PROTEIN,
---------CORN
7.5
Oats
12.5
SOYBEAN MEAL
48.8
DICALCIUM PHOSPHATE
0
LIMESTONE
0
Tylan-10 contains 10 grams Tylosin/lb.
CuSO4-5H20 contains 25 percent copper.
PLACE YOUR ANSWERS HERE:
Percent
CORN
Oats
SOYBEAN MEAL
DICAL
LIMESTONE
SALT
TM Premix
Se PREMIX
VIT Premix
TYLAN-10
CU-SULFATE
OTHER
TOTAL
57.6
15
24.4
.6516756
.937047
0.25
0.10
0.05
0.30
0.40
0.10
.2112772
------
100
PERCENT LYSINE IN RATION =
TON
1152
300
488
13.03351
18.74094
5
2
1
6
8
2
4.225545
-----2000
.9864601
CALCIUM,
---------.02
.10
.25
24.0
38
PHOSPHORUS,
---------.29
.44
.60
18.5
0
ANSWERS:
3
ANSC 221, Homework 5
ALGEBRAIC SOLUTION:
PEARSON SQUARE SOLUTION:
(100)( .181 ) = ( .075 )(X) + ( .125 )( 15 ) + (100- 3 - 15 -X)( .488 )
PROTEIN
CORN
Oats
SBM
18.1
= .075 X + 1.875
18.1
= .075 X + 1.875
18.1 - 40.016 - 1.875
= .075
-23.791
=
-.413 X
57.6
= X
24.4
=
82
( 15 )
+ ( 82 -X)( .488 )
+ 40.016 - .488 X
X - .488 X
( .125 ) =
STEP 2: (100 lbs) ( .181 ) = 18.1
18.1 - 1.875 = 16.225
STEP 3: 100- 15 - 3 = 82
16.225 / 82 =
- X
STEP 4:
---------- 29
:
:
: 19.8
:
:
:
48.8 ---------12.3
--------41.3
CORN = 57.6
Oats = 15
SBM = 24.4
7.5
MINERALS
--
.6 PERCENT CA
AND
1.875
(100-AMT Oats-AMT EMPTY)
19.8
29
/
41.3
12.3
/
.5 PERCENT P
P IN GRAIN = (.0029)( 57.6 ) + (.0044)( 15 ) + (.006)( 24.4 ) =
CORN
Oats
SBM
.16704
+
.066
+
.1464
=
.37944
P STILL NEEDED = .5 - .37944 = .12056
AMT DICAL TO USE = .12056 / .185 = .6516756
CA IN GRAIN + DICAL = (.0002)( 57.6 ) + (.0010)( 15 ) + (.0025)( 24.4 ) + (.24)( .6516756 ) =
.01152
+
.015
+
.061
+
.1564022
CA STILL NEEDED = .6 - .2439222 = .3560778
LIMESTONE TO USE TO GET .3560778 LBS CA = .3560778 / .38 =
TM Premix: 2 LBS/TON = 1 Lb/1000 = .5 lb/100 = .5%
Se Premix: 1 LB/TON = .5 lb/1000 = .05 lb/100 = .05%
Vit Premix: 6 LB/TON = 3 lb/1000 = .3 lb/100 = .3%
TYLAN-10: 80 g/ton = 40 g/1000 lb = 4 g/100 lb coming from
a compound with 10 g/lb of the tylan we want.
Therefore 4 g = X (10 g/lb) or 4/10 = .4 lbs TYLAN-10
CuSO4: 250 ppm = .025% Cu ; compound is 25% Cu so
.025 lb = X (.25) , or add .1 lb CuSO4 per 100 lbs feed.
OTHER should be calculated by subtracting all feeds from 100.0
.937047
.2439222
x
82
=
57.6
41.3
x
82
=
24.4
4
ANSC 221
HOMEWORK 5
NAME -------------------------RATION BALANCING--SWINE TYPE
2 BASAL FEEDS AND MINERALS
---ANSWERS--FIXED AMOUNT OF Oats
BALANCE 100 POUNDS OF A RATION FOR SWINE TO CONTAIN
12.3 PERCENT PROTEIN.
MAKE THE RATION CONTAIN 10 PERCENT Oats AND USE CORN AND SOYBEAN MEAL TO SUPPLY
THE NEEDED AMOUNT OF ADDITIONAL PROTEIN.
LEAVE
3 PERCENT OF THE RATION FREE FOR VITAMINS, MINERALS, ETC.
BALANCE THE RATION TO CONTAIN .6 PERCENT CALCIUM AND .5 PERCENT PHOSPHORUS.
USE THE FOLLOWING INGREDIENT COMPOSITION (values are in percent)
Make it contain: 2 lbs/Ton of Trace Mineral premix
6 lbs/Ton of Vitamin premix
0.25% salt
250 PPM Copper from Copper Sulfate
1 lb per Ton of Selenium premix
80 Grams per Ton Tylosin
After balancing the ration, CALCULATE the percent LYSINE.
PROTEIN,
---------CORN
8.1
Oats
12.7
SOYBEAN MEAL
48.7
DICALCIUM PHOSPHATE
0
LIMESTONE
0
Tylan-10 contains 10 grams Tylosin/lb.
CuSO4-5H20 contains 25 percent copper.
CALCIUM,
---------.02
.10
.25
24.0
38
PLACE YOUR ANSWERS HERE:
Percent
TON
CORN
Oats
SOYBEAN MEAL
DICAL
LIMESTONE
SALT
TM Premix
Se PREMIX
VIT Premix
TYLAN-10
CU-SULFATE
OTHER
TOTAL
77.2
1544
10
200
9.800003
196.0001
.9368649
18.7373
.8558223
17.11645
0.25
5
0.10
2
0.05
1
0.30
6
0.40
8
0.10
2
7.312775E-03
----------100
2000
PERCENT LYSINE IN RATION =
.5645201
.1462555
PHOSPHORUS,
---------.29
.44
.60
18.5
0
ANSWERS:
4
ANSC 221, Homework 5
ALGEBRAIC SOLUTION:
PEARSON SQUARE SOLUTION:
(100)( .123 ) = ( .081 )(X) + ( .127 )( 10 ) + (100- 3 - 10 -X)( .487 )
PROTEIN
CORN
Oats
SBM
12.3
= .081 X + 1.27
12.3
= .081 X + 1.27
12.3 - 42.369 - 1.27
= .081
-31.339
=
-.406 X
77.2
= X
9.800003
=
87
( 10 )
+ ( 87 -X)( .487 )
+ 42.369 - .487 X
X - .487 X
( .127 ) =
1.27
STEP 2: (100 lbs) ( .123 ) = 12.3
12.3 - 1.27 = 11.03
STEP 3: 100- 10 - 3
11.03 /
- X
= 87
87 =
(100-AMT Oats-AMT EMPTY)
12.7
STEP 4:
---------- 36
36
:
:
: 12.7
:
:
:
48.7 ---------4.599999
8.1
/
40.6
x
4.599999
87
=
/
40.6
9.800003
--------40.6
CORN = 77.2
Oats = 10
SBM = 9.800003
MINERALS
--
.6 PERCENT CA
AND
.5 PERCENT P
P IN GRAIN = (.0029)( 77.2 ) + (.0044)( 10 ) + (.006)( 9.800003 ) =
CORN
Oats
SBM
.22388
+
.044
+
5.880002E-02
=
P STILL NEEDED = .5 - .32668 = .17332
AMT DICAL TO USE = .17332 / .185 = .9368649
CA IN GRAIN + DICAL = (.0002)( 77.2 ) + (.0010)( 10 ) + (.0025)( 9.800003 ) + (.24)( .9368649 ) =
.01544
+
.01
+
2.450001E-02
+
.2248476
CA STILL NEEDED = .6 - .2747876 = .3252124
LIMESTONE TO USE TO GET .3252124 LBS CA = .3252124 / .38 =
TM Premix: 2 LBS/TON = 1 Lb/1000 = .5 lb/100 = .5%
Se Premix: 1 LB/TON = .5 lb/1000 = .05 lb/100 = .05%
Vit Premix: 6 LB/TON = 3 lb/1000 = .3 lb/100 = .3%
TYLAN-10: 80 g/ton = 40 g/1000 lb = 4 g/100 lb coming from
a compound with 10 g/lb of the tylan we want.
Therefore 4 g = X (10 g/lb) or 4/10 = .4 lbs TYLAN-10
CuSO4: 250 ppm = .025% Cu ; compound is 25% Cu so
.025 lb = X (.25) , or add .1 lb CuSO4 per 100 lbs feed.
OTHER should be calculated by subtracting all feeds from 100.0
.8558223
.2747876
.32668
77.2
x
87
=
5
ANSC 221
HOMEWORK 5
NAME -------------------------RATION BALANCING--SWINE TYPE
2 BASAL FEEDS AND MINERALS
---ANSWERS--FIXED AMOUNT OF Oats
BALANCE 100 POUNDS OF A RATION FOR SWINE TO CONTAIN
19.6 PERCENT PROTEIN.
MAKE THE RATION CONTAIN 10 PERCENT Oats AND USE CORN AND SOYBEAN MEAL TO SUPPLY
THE NEEDED AMOUNT OF ADDITIONAL PROTEIN.
LEAVE
3 PERCENT OF THE RATION FREE FOR VITAMINS, MINERALS, ETC.
BALANCE THE RATION TO CONTAIN .6 PERCENT CALCIUM AND .5 PERCENT PHOSPHORUS.
USE THE FOLLOWING INGREDIENT COMPOSITION (values are in percent)
Make it contain: 2 lbs/Ton of Trace Mineral premix
6 lbs/Ton of Vitamin premix
0.25% salt
250 PPM Copper from Copper Sulfate
1 lb per Ton of Selenium premix
80 Grams per Ton Tylosin
After balancing the ration, CALCULATE the percent LYSINE.
PROTEIN,
---------CORN
8.8
Oats
11.1
SOYBEAN MEAL
49.6
DICALCIUM PHOSPHATE
0
LIMESTONE
0
Tylan-10 contains 10 grams Tylosin/lb.
CuSO4-5H20 contains 25 percent copper.
PLACE YOUR ANSWERS HERE:
Percent
CORN
Oats
SOYBEAN MEAL
DICAL
LIMESTONE
SALT
TM Premix
Se PREMIX
VIT Premix
TYLAN-10
CU-SULFATE
OTHER
TOTAL
60.4
10
26.6
.6553515
.931936
0.25
0.10
0.05
0.30
0.40
0.10
.2127125
------
100
PERCENT LYSINE IN RATION =
TON
1208
200
532
13.10703
18.63872
5
2
1
6
8
2
4.254251
-----2000
1.00804
CALCIUM,
---------.02
.10
.25
24.0
38
PHOSPHORUS,
---------.29
.44
.60
18.5
0
ANSWERS:
5
ANSC 221, Homework 5
ALGEBRAIC SOLUTION:
PEARSON SQUARE SOLUTION:
(100)( .196 ) = ( .088 )(X) + ( .111 )( 10 ) + (100- 3 - 10 -X)( .496 )
PROTEIN
CORN
Oats
SBM
19.6
= .088 X + 1.11
19.6
= .088 X + 1.11
19.6 - 43.152 - 1.11
= .088
-24.662
=
-.408 X
60.4
= X
26.6
=
87
( 10 )
+ ( 87 -X)( .496 )
+ 43.152 - .496 X
X - .496 X
( .111 ) =
STEP 2: (100 lbs) ( .196 ) = 19.6
19.6 - 1.11 = 18.49
STEP 3: 100- 10 - 3
18.49 /
- X
= 87
87 =
STEP 4:
---------- 28.3
:
:
: 21.3
:
:
:
49.6 ---------12.5
--------40.8
CORN = 60.4
Oats = 10
SBM = 26.6
8.8
MINERALS
--
.6 PERCENT CA
AND
1.11
(100-AMT Oats-AMT EMPTY)
21.3
28.3
/
40.8
x
87
=
60.4
12.5
/
40.8
x
87
=
26.6
.5 PERCENT P
P IN GRAIN = (.0029)( 60.4 ) + (.0044)( 10 ) + (.006)( 26.6 ) =
CORN
Oats
SBM
.17516
+
.044
+
.1596
=
.37876
P STILL NEEDED = .5 - .37876 = .12124
AMT DICAL TO USE = .12124 / .185 = .6553515
CA IN GRAIN + DICAL = (.0002)( 60.4 ) + (.0010)( 10 ) + (.0025)( 26.6 ) + (.24)( .6553515 ) =
.01208
+
.01
+
6.649999E-02
+
.1572843
CA STILL NEEDED = .6 - .2458643 = .3541357
LIMESTONE TO USE TO GET .3541357 LBS CA = .3541357 / .38 =
TM Premix: 2 LBS/TON = 1 Lb/1000 = .5 lb/100 = .5%
Se Premix: 1 LB/TON = .5 lb/1000 = .05 lb/100 = .05%
Vit Premix: 6 LB/TON = 3 lb/1000 = .3 lb/100 = .3%
TYLAN-10: 80 g/ton = 40 g/1000 lb = 4 g/100 lb coming from
a compound with 10 g/lb of the tylan we want.
Therefore 4 g = X (10 g/lb) or 4/10 = .4 lbs TYLAN-10
CuSO4: 250 ppm = .025% Cu ; compound is 25% Cu so
.025 lb = X (.25) , or add .1 lb CuSO4 per 100 lbs feed.
OTHER should be calculated by subtracting all feeds from 100.0
.931936
.2458643
6
ANSC 221
HOMEWORK 5
NAME -------------------------RATION BALANCING--SWINE TYPE
2 BASAL FEEDS AND MINERALS
---ANSWERS--FIXED AMOUNT OF Oats
BALANCE 100 POUNDS OF A RATION FOR SWINE TO CONTAIN
16.1 PERCENT PROTEIN.
MAKE THE RATION CONTAIN 12 PERCENT Oats AND USE CORN AND SOYBEAN MEAL TO SUPPLY
THE NEEDED AMOUNT OF ADDITIONAL PROTEIN.
LEAVE
3 PERCENT OF THE RATION FREE FOR VITAMINS, MINERALS, ETC.
BALANCE THE RATION TO CONTAIN .6 PERCENT CALCIUM AND .5 PERCENT PHOSPHORUS.
USE THE FOLLOWING INGREDIENT COMPOSITION (values are in percent)
Make it contain: 2 lbs/Ton of Trace Mineral premix
6 lbs/Ton of Vitamin premix
0.25% salt
250 PPM Copper from Copper Sulfate
1 lb per Ton of Selenium premix
80 Grams per Ton Tylosin
After balancing the ration, CALCULATE the percent LYSINE.
PROTEIN,
---------CORN
8.8
Oats
11.1
SOYBEAN MEAL
47.5
DICALCIUM PHOSPHATE
0
LIMESTONE
0
Tylan-10 contains 10 grams Tylosin/lb.
CuSO4-5H20 contains 25 percent copper.
PLACE YOUR ANSWERS HERE:
Percent
CORN
Oats
SOYBEAN MEAL
DICAL
LIMESTONE
SALT
TM Premix
Se PREMIX
VIT Premix
TYLAN-10
CU-SULFATE
OTHER
TOTAL
66.2
12
18.8
.7698378
.9026288
0.25
0.10
0.05
0.30
0.40
0.10
.1275333
------
100
PERCENT LYSINE IN RATION =
TON
1324
240
376.0001
15.39676
18.05258
5
2
1
6
8
2
2.550666
-----2000
.8167201
CALCIUM,
---------.02
.10
.25
24.0
38
PHOSPHORUS,
---------.29
.44
.60
18.5
0
ANSWERS:
6
ANSC 221, Homework 5
ALGEBRAIC SOLUTION:
PEARSON SQUARE SOLUTION:
(100)( .161 ) = ( .088 )(X) + ( .111 )( 12 ) + (100- 3 - 12 -X)( .475 )
PROTEIN
CORN
Oats
SBM
16.1
= .088 X + 1.332
16.1
= .088 X + 1.332
16.1 - 40.375 - 1.332
= .088
-25.607
=
-.387 X
66.2
= X
18.8
=
85
( 12 )
+ ( 85 -X)( .475 )
+ 40.375 - .475 X
X - .475 X
( .111 ) =
1.332
STEP 2: (100 lbs) ( .161 ) = 16.1
16.1 - 1.332 = 14.768
STEP 3: 100- 12 - 3 = 85
14.768 / 85 =
- X
STEP 4:
---------:
:
: 17.4
:
:
:
47.5 ---------8.8
30.1
(100-AMT Oats-AMT EMPTY)
17.4
30.1
8.599999
--------38.7
CORN = 66.2
Oats = 12
SBM = 18.8
--
.6 PERCENT CA
AND
.5 PERCENT P
P IN GRAIN = (.0029)( 66.2 ) + (.0044)( 12 ) + (.006)( 18.8 ) =
CORN
Oats
SBM
.19198
+
.0528
+
.1128
=
.35758
P STILL NEEDED = .5 - .35758 = .14242
AMT DICAL TO USE = .14242 / .185 = .7698378
CA IN GRAIN + DICAL = (.0002)( 66.2 ) + (.0010)( 12 ) + (.0025)( 18.8 ) + (.24)( .7698378 ) =
.01324
+
.012
+
4.700001E-02
+
.1847611
CA STILL NEEDED = .6 - .2570011 = .342999
LIMESTONE TO USE TO GET .342999 LBS CA = .342999 / .38 = .9026288
TM Premix: 2 LBS/TON = 1 Lb/1000 = .5 lb/100 = .5%
Se Premix: 1 LB/TON = .5 lb/1000 = .05 lb/100 = .05%
Vit Premix: 6 LB/TON = 3 lb/1000 = .3 lb/100 = .3%
TYLAN-10: 80 g/ton = 40 g/1000 lb = 4 g/100 lb coming from
a compound with 10 g/lb of the tylan we want.
Therefore 4 g = X (10 g/lb) or 4/10 = .4 lbs TYLAN-10
CuSO4: 250 ppm = .025% Cu ; compound is 25% Cu so
.025 lb = X (.25) , or add .1 lb CuSO4 per 100 lbs feed.
OTHER should be calculated by subtracting all feeds from 100.0
38.7
8.599999
18.8
MINERALS
/
.2570011
x
/
85
38.7
=
x
66.2
85
=
7
ANSC 221
HOMEWORK 5
NAME -------------------------RATION BALANCING--SWINE TYPE
2 BASAL FEEDS AND MINERALS
---ANSWERS--FIXED AMOUNT OF Oats
BALANCE 100 POUNDS OF A RATION FOR SWINE TO CONTAIN
14.3 PERCENT PROTEIN.
MAKE THE RATION CONTAIN 9 PERCENT Oats AND USE CORN AND SOYBEAN MEAL TO SUPPLY
THE NEEDED AMOUNT OF ADDITIONAL PROTEIN.
LEAVE
3 PERCENT OF THE RATION FREE FOR VITAMINS, MINERALS, ETC.
BALANCE THE RATION TO CONTAIN .6 PERCENT CALCIUM AND .5 PERCENT PHOSPHORUS.
USE THE FOLLOWING INGREDIENT COMPOSITION (values are in percent)
Make it contain: 2 lbs/Ton of Trace Mineral premix
6 lbs/Ton of Vitamin premix
0.25% salt
250 PPM Copper from Copper Sulfate
1 lb per Ton of Selenium premix
80 Grams per Ton Tylosin
After balancing the ration, CALCULATE the percent LYSINE.
PROTEIN,
---------CORN
8.5
Oats
12.2
SOYBEAN MEAL
45.5
DICALCIUM PHOSPHATE
0
LIMESTONE
0
Tylan-10 contains 10 grams Tylosin/lb.
CuSO4-5H20 contains 25 percent copper.
CALCIUM,
---------.02
.10
.25
24.0
38
PLACE YOUR ANSWERS HERE:
Percent
TON
CORN
Oats
SOYBEAN MEAL
DICAL
LIMESTONE
SALT
TM Premix
Se PREMIX
VIT Premix
TYLAN-10
CU-SULFATE
OTHER
TOTAL
72.5
1450
9
180
15.5
310
.8494595
16.98919
.878631
17.57262
0.25
5
0.10
2
0.05
1
0.30
6
0.40
8
0.10
2
7.190943E-02
----------100
2000
PERCENT LYSINE IN RATION =
.7077
1.438189
PHOSPHORUS,
---------.29
.44
.60
18.5
0
ANSWERS:
7
ANSC 221, Homework 5
ALGEBRAIC SOLUTION:
PEARSON SQUARE SOLUTION:
(100)( .143 ) = ( .085 )(X) + ( .122 )( 9 ) + (100- 3 - 9 -X)( .455 )
PROTEIN
CORN
Oats
SBM
14.3
= .085 X
14.3
= .085 X
14.3 - 40.04 - 1.098
-26.838
=
-.37
72.5
= X
15.5
=
88
+
+
=
X
( 9 )
1.098
+ ( 88 -X)( .455 )
1.098 + 40.04 - .455 X
.085 X - .455 X
( .122 ) =
STEP 2: (100 lbs) ( .143 ) = 14.3
14.3 - 1.098 = 13.202
STEP 3: 100- 9 - 3
13.202
- X
=
/
88
88
STEP 4:
---------- 30.5
:
:
: 15
:
:
:
45.5 ---------6.5
--------37
CORN = 72.5
Oats = 9
SBM = 15.5
8.5
MINERALS
--
.6 PERCENT CA
AND
1.098
=
(100-AMT Oats-AMT EMPTY)
15
30.5
6.5
.5 PERCENT P
P IN GRAIN = (.0029)( 72.5 ) + (.0044)( 9 ) + (.006)( 15.5 ) =
CORN
Oats
SBM
.21025
+
.0396
+
.093
=
.34285
P STILL NEEDED = .5 - .34285 = .15715
AMT DICAL TO USE = .15715 / .185 = .8494595
CA IN GRAIN + DICAL = (.0002)( 72.5 ) + (.0010)( 9 ) + (.0025)( 15.5 ) + (.24)( .8494595 ) =
.0145
+
9.000001E-03
+
.03875
+
.2038703
CA STILL NEEDED = .6 - .2661203 = .3338798
LIMESTONE TO USE TO GET .3338798 LBS CA = .3338798 / .38 =
TM Premix: 2 LBS/TON = 1 Lb/1000 = .5 lb/100 = .5%
Se Premix: 1 LB/TON = .5 lb/1000 = .05 lb/100 = .05%
Vit Premix: 6 LB/TON = 3 lb/1000 = .3 lb/100 = .3%
TYLAN-10: 80 g/ton = 40 g/1000 lb = 4 g/100 lb coming from
a compound with 10 g/lb of the tylan we want.
Therefore 4 g = X (10 g/lb) or 4/10 = .4 lbs TYLAN-10
CuSO4: 250 ppm = .025% Cu ; compound is 25% Cu so
.025 lb = X (.25) , or add .1 lb CuSO4 per 100 lbs feed.
OTHER should be calculated by subtracting all feeds from 100.0
.878631
.2661203
/
/
37
37
x
x
88
88
=
=
72.5
15.5
8
ANSC 221
HOMEWORK 5
NAME -------------------------RATION BALANCING--SWINE TYPE
2 BASAL FEEDS AND MINERALS
---ANSWERS--FIXED AMOUNT OF Oats
BALANCE 100 POUNDS OF A RATION FOR SWINE TO CONTAIN
18.6 PERCENT PROTEIN.
MAKE THE RATION CONTAIN 18 PERCENT Oats AND USE CORN AND SOYBEAN MEAL TO SUPPLY
THE NEEDED AMOUNT OF ADDITIONAL PROTEIN.
LEAVE
3 PERCENT OF THE RATION FREE FOR VITAMINS, MINERALS, ETC.
BALANCE THE RATION TO CONTAIN .6 PERCENT CALCIUM AND .5 PERCENT PHOSPHORUS.
USE THE FOLLOWING INGREDIENT COMPOSITION (values are in percent)
Make it contain: 2 lbs/Ton of Trace Mineral premix
6 lbs/Ton of Vitamin premix
0.25% salt
250 PPM Copper from Copper Sulfate
1 lb per Ton of Selenium premix
80 Grams per Ton Tylosin
After balancing the ration, CALCULATE the percent LYSINE.
PROTEIN,
---------CORN
8.8
Oats
12.1
SOYBEAN MEAL
49.9
DICALCIUM PHOSPHATE
0
LIMESTONE
0
Tylan-10 contains 10 grams Tylosin/lb.
CuSO4-5H20 contains 25 percent copper.
PLACE YOUR ANSWERS HERE:
Percent
CORN
Oats
SOYBEAN MEAL
DICAL
LIMESTONE
SALT
TM Premix
Se PREMIX
VIT Premix
TYLAN-10
CU-SULFATE
OTHER
TOTAL
56
18
23
.6508108
.9397511
0.25
0.10
0.05
0.30
0.40
0.10
.209438
------
100
PERCENT LYSINE IN RATION =
TON
1120
360
460
13.01622
18.79502
5
2
1
6
8
2
4.188759
-----2000
.9714
CALCIUM,
---------.02
.10
.25
24.0
38
PHOSPHORUS,
---------.29
.44
.60
18.5
0
ANSWERS:
8
ANSC 221, Homework 5
ALGEBRAIC SOLUTION:
PEARSON SQUARE SOLUTION:
(100)( .186 ) = ( .088 )(X) + ( .121 )( 18 ) + (100- 3 - 18 -X)( .499 )
PROTEIN
CORN
Oats
SBM
18.6
= .088 X + 2.178
18.6
= .088 X + 2.178
18.6 - 39.421 - 2.178
= .088
-22.999
=
-.411 X
56
= X
23
=
79
( 18 )
+ ( 79 -X)( .499 )
+ 39.421 - .499 X
X - .499 X
( .121 ) =
STEP 2: (100 lbs) ( .186 ) = 18.6
18.6 - 2.178 = 16.422
STEP 3: 100- 18 - 3 =
16.422 / 79
- X
79
(100-AMT Oats-AMT EMPTY)
= 20.8
STEP 4:
---------- 29.1
:
:
: 20.8
:
:
:
49.9 ---------12
--------41.1
CORN = 56
Oats = 18
SBM = 23
8.8
MINERALS
--
.6 PERCENT CA
AND
.5 PERCENT P
P IN GRAIN = (.0029)( 56 ) + (.0044)( 18 ) + (.006)( 23 ) =
CORN
Oats
SBM
.1624
+
.0792
+
.138
=
.3796
P STILL NEEDED = .5 - .3796 = .1204
AMT DICAL TO USE = .1204 / .185 = .6508108
CA IN GRAIN + DICAL = (.0002)( 56 ) + (.0010)( 18 ) + (.0025)( 23 ) + (.24)( .6508108 ) =
.0112
+
.018
+
.0575
+
.1561946
CA STILL NEEDED = .6 - .2428946 = .3571054
LIMESTONE TO USE TO GET .3571054 LBS CA = .3571054 / .38 =
TM Premix: 2 LBS/TON = 1 Lb/1000 = .5 lb/100 = .5%
Se Premix: 1 LB/TON = .5 lb/1000 = .05 lb/100 = .05%
Vit Premix: 6 LB/TON = 3 lb/1000 = .3 lb/100 = .3%
TYLAN-10: 80 g/ton = 40 g/1000 lb = 4 g/100 lb coming from
a compound with 10 g/lb of the tylan we want.
Therefore 4 g = X (10 g/lb) or 4/10 = .4 lbs TYLAN-10
CuSO4: 250 ppm = .025% Cu ; compound is 25% Cu so
.025 lb = X (.25) , or add .1 lb CuSO4 per 100 lbs feed.
OTHER should be calculated by subtracting all feeds from 100.0
2.178
.9397511
.2428946
29.1
12
/
/
41.1
41.1
x
x
79
=
79
=
23
56
9
ANSC 221
HOMEWORK 5
NAME -------------------------RATION BALANCING--SWINE TYPE
2 BASAL FEEDS AND MINERALS
---ANSWERS--FIXED AMOUNT OF Oats
BALANCE 100 POUNDS OF A RATION FOR SWINE TO CONTAIN
13.8 PERCENT PROTEIN.
MAKE THE RATION CONTAIN 13 PERCENT Oats AND USE CORN AND SOYBEAN MEAL TO SUPPLY
THE NEEDED AMOUNT OF ADDITIONAL PROTEIN.
LEAVE
3 PERCENT OF THE RATION FREE FOR VITAMINS, MINERALS, ETC.
BALANCE THE RATION TO CONTAIN .6 PERCENT CALCIUM AND .5 PERCENT PHOSPHORUS.
USE THE FOLLOWING INGREDIENT COMPOSITION (values are in percent)
Make it contain: 2 lbs/Ton of Trace Mineral premix
6 lbs/Ton of Vitamin premix
0.25% salt
250 PPM Copper from Copper Sulfate
1 lb per Ton of Selenium premix
80 Grams per Ton Tylosin
After balancing the ration, CALCULATE the percent LYSINE.
PROTEIN,
---------CORN
8.6
Oats
12.9
SOYBEAN MEAL
45.4
DICALCIUM PHOSPHATE
0
LIMESTONE
0
Tylan-10 contains 10 grams Tylosin/lb.
CuSO4-5H20 contains 25 percent copper.
CALCIUM,
---------.02
.10
.25
24.0
38
PLACE YOUR ANSWERS HERE:
Percent
TON
CORN
Oats
SOYBEAN MEAL
DICAL
LIMESTONE
SALT
TM Premix
Se PREMIX
VIT Premix
TYLAN-10
CU-SULFATE
OTHER
TOTAL
70.7
1414
13
260
13.3
266.0001
.8538918
17.07784
.8807263
17.61453
0.25
5
0.10
2
0.05
1
0.30
6
0.40
8
0.10
2
6.538177E-02
----------100
2000
PERCENT LYSINE IN RATION =
.6788201
1.307635
PHOSPHORUS,
---------.29
.44
.60
18.5
0
ANSWERS:
9
ANSC 221, Homework 5
ALGEBRAIC SOLUTION:
PEARSON SQUARE SOLUTION:
(100)( .138 ) = ( .086 )(X) + ( .129 )( 13 ) + (100- 3 - 13 -X)( .454 )
PROTEIN
CORN
Oats
SBM
13.8
= .086 X + 1.677
13.8
= .086 X + 1.677
13.8 - 38.136 - 1.677
= .086
-26.013
=
-.368 X
70.7
= X
13.3
=
84
( 13 )
+ ( 84 -X)( .454 )
+ 38.136 - .454 X
X - .454 X
( .129 ) =
1.677
STEP 2: (100 lbs) ( .138 ) = 13.8
13.8 - 1.677 = 12.123
STEP 3: 100- 13 - 3 = 84
12.123 / 84 =
- X
STEP 4:
---------:
:
: 14.4
:
:
:
45.4 ---------8.6
31
31
(100-AMT Oats-AMT EMPTY)
14.4
/
5.799999
36.8
x
5.799999
13.3
--------36.8
CORN = 70.7
Oats = 13
SBM = 13.3
MINERALS
--
.6 PERCENT CA
AND
.5 PERCENT P
P IN GRAIN = (.0029)( 70.7 ) + (.0044)( 13 ) + (.006)( 13.3 ) =
CORN
Oats
SBM
.20503
+
.0572
+
7.980002E-02
P STILL NEEDED = .5 - .34203 = .15797
AMT DICAL TO USE = .15797 / .185 = .8538918
CA IN GRAIN + DICAL = (.0002)( 70.7 ) + (.0010)( 13 ) + (.0025)( 13.3 ) + (.24)( .8538918 ) =
.01414
+
.013
+
3.325001E-02
+
.204934
CA STILL NEEDED = .6 - .265324 = .334676
LIMESTONE TO USE TO GET .334676 LBS CA = .334676 / .38 = .8807263
TM Premix: 2 LBS/TON = 1 Lb/1000 = .5 lb/100 = .5%
Se Premix: 1 LB/TON = .5 lb/1000 = .05 lb/100 = .05%
Vit Premix: 6 LB/TON = 3 lb/1000 = .3 lb/100 = .3%
TYLAN-10: 80 g/ton = 40 g/1000 lb = 4 g/100 lb coming from
a compound with 10 g/lb of the tylan we want.
Therefore 4 g = X (10 g/lb) or 4/10 = .4 lbs TYLAN-10
CuSO4: 250 ppm = .025% Cu ; compound is 25% Cu so
.025 lb = X (.25) , or add .1 lb CuSO4 per 100 lbs feed.
OTHER should be calculated by subtracting all feeds from 100.0
.265324
=
.34203
84
=
70.7
/
36.8
x
84
=
10
ANSC 221
HOMEWORK 5
NAME -------------------------RATION BALANCING--SWINE TYPE
2 BASAL FEEDS AND MINERALS
---ANSWERS--FIXED AMOUNT OF Oats
BALANCE 100 POUNDS OF A RATION FOR SWINE TO CONTAIN
12.8 PERCENT PROTEIN.
MAKE THE RATION CONTAIN 13 PERCENT Oats AND USE CORN AND SOYBEAN MEAL TO SUPPLY
THE NEEDED AMOUNT OF ADDITIONAL PROTEIN.
LEAVE
3 PERCENT OF THE RATION FREE FOR VITAMINS, MINERALS, ETC.
BALANCE THE RATION TO CONTAIN .6 PERCENT CALCIUM AND .5 PERCENT PHOSPHORUS.
USE THE FOLLOWING INGREDIENT COMPOSITION (values are in percent)
Make it contain: 2 lbs/Ton of Trace Mineral premix
6 lbs/Ton of Vitamin premix
0.25% salt
250 PPM Copper from Copper Sulfate
1 lb per Ton of Selenium premix
80 Grams per Ton Tylosin
After balancing the ration, CALCULATE the percent LYSINE.
PROTEIN,
---------CORN
9.1
Oats
12.3
SOYBEAN MEAL
44
DICALCIUM PHOSPHATE
0
LIMESTONE
0
Tylan-10 contains 10 grams Tylosin/lb.
CuSO4-5H20 contains 25 percent copper.
PLACE YOUR ANSWERS HERE:
Percent
CORN
Oats
SOYBEAN MEAL
DICAL
LIMESTONE
SALT
TM Premix
Se PREMIX
VIT Premix
TYLAN-10
CU-SULFATE
OTHER
TOTAL
73.8
13
10.2
.9058379
.8666814
0.25
0.10
0.05
0.30
0.40
0.10
.0274806
------
100
PERCENT LYSINE IN RATION =
TON
1476
260
203.9999
18.11676
17.33363
5
2
1
6
8
2
.549612
-----2000
.5969799
CALCIUM,
---------.02
.10
.25
24.0
38
PHOSPHORUS,
---------.29
.44
.60
18.5
0
ANSWERS:
10
ANSC 221, Homework 5
ALGEBRAIC SOLUTION:
PEARSON SQUARE SOLUTION:
(100)( .128 ) = ( 9.100001E-02 )(X) + ( .123 )( 13 ) + (100- 3 - 13 -X)( .44 )
PROTEIN
CORN
Oats
SBM
( 13 )
12.8
= 9.100001E-02 X + 1.599
+ ( 84 -X)( .44 )
12.8
= 9.100001E-02 X + 1.599 + 36.96 - .44 X
12.8 - 36.96 - 1.599
= 9.100001E-02 X - .44 X
-25.759
=
-.349 X
73.8
= X
10.2
=
84
STEP 3: 100- 13 - 3 = 84
11.201 / 84 =
- X
44
--
.6 PERCENT CA
AND
1.599
STEP 2: (100 lbs) ( .128 ) = 12.8
12.8 - 1.599 = 11.201
9.1
MINERALS
( .123 ) =
STEP 4:
---------- 30.7
:
:
: 13.3
:
:
:
---------4.2
--------34.9
CORN = 73.8
Oats = 13
SBM = 10.2
(100-AMT Oats-AMT EMPTY)
13.3
30.7
4.2
/
6.119998E-02
=
/
34.9
34.9
x
.5 PERCENT P
P IN GRAIN = (.0029)( 73.8 ) + (.0044)( 13 ) + (.006)( 10.2 ) =
CORN
Oats
SBM
.21402
+
.0572
+
P STILL NEEDED = .5 - .33242 = .16758
AMT DICAL TO USE = .16758 / .185 = .9058379
CA IN GRAIN + DICAL = (.0002)( 73.8 ) + (.0010)( 13 ) + (.0025)( 10.2 ) + (.24)( .9058379 ) =
.01476
+
.013
+
2.549999E-02
+
.2174011
CA STILL NEEDED = .6 - .2706611 = .3293389
LIMESTONE TO USE TO GET .3293389 LBS CA = .3293389 / .38 =
TM Premix: 2 LBS/TON = 1 Lb/1000 = .5 lb/100 = .5%
Se Premix: 1 LB/TON = .5 lb/1000 = .05 lb/100 = .05%
Vit Premix: 6 LB/TON = 3 lb/1000 = .3 lb/100 = .3%
TYLAN-10: 80 g/ton = 40 g/1000 lb = 4 g/100 lb coming from
a compound with 10 g/lb of the tylan we want.
Therefore 4 g = X (10 g/lb) or 4/10 = .4 lbs TYLAN-10
CuSO4: 250 ppm = .025% Cu ; compound is 25% Cu so
.025 lb = X (.25) , or add .1 lb CuSO4 per 100 lbs feed.
OTHER should be calculated by subtracting all feeds from 100.0
.8666814
.2706611
.33242
x
84
=
73.8
84
=
10.2
11
ANSC 221
HOMEWORK 5
NAME -------------------------RATION BALANCING--SWINE TYPE
2 BASAL FEEDS AND MINERALS
---ANSWERS--FIXED AMOUNT OF Oats
BALANCE 100 POUNDS OF A RATION FOR SWINE TO CONTAIN
12.8 PERCENT PROTEIN.
MAKE THE RATION CONTAIN 5 PERCENT Oats AND USE CORN AND SOYBEAN MEAL TO SUPPLY
THE NEEDED AMOUNT OF ADDITIONAL PROTEIN.
LEAVE
3 PERCENT OF THE RATION FREE FOR VITAMINS, MINERALS, ETC.
BALANCE THE RATION TO CONTAIN .6 PERCENT CALCIUM AND .5 PERCENT PHOSPHORUS.
USE THE FOLLOWING INGREDIENT COMPOSITION (values are in percent)
Make it contain: 2 lbs/Ton of Trace Mineral premix
6 lbs/Ton of Vitamin premix
0.25% salt
250 PPM Copper from Copper Sulfate
1 lb per Ton of Selenium premix
80 Grams per Ton Tylosin
After balancing the ration, CALCULATE the percent LYSINE.
PROTEIN,
---------CORN
7.5
Oats
12.5
SOYBEAN MEAL
45.7
DICALCIUM PHOSPHATE
0
LIMESTONE
0
Tylan-10 contains 10 grams Tylosin/lb.
CuSO4-5H20 contains 25 percent copper.
CALCIUM,
---------.02
.10
.25
24.0
38
PLACE YOUR ANSWERS HERE:
Percent
TON
CORN
Oats
SOYBEAN MEAL
DICAL
LIMESTONE
SALT
TM Premix
Se PREMIX
VIT Premix
TYLAN-10
CU-SULFATE
OTHER
TOTAL
78.2
1564
5
100
13.8
276.0001
.9103783
18.20757
.8588664
17.17733
0.25
5
0.10
2
0.05
1
0.30
6
0.40
8
0.10
2
3.075528E-02
----------100
2000
PERCENT LYSINE IN RATION =
.6336201
.6151056
PHOSPHORUS,
---------.29
.44
.60
18.5
0
ANSWERS:
11
ANSC 221, Homework 5
ALGEBRAIC SOLUTION:
PEARSON SQUARE SOLUTION:
(100)( .128 ) = ( .075 )(X) + ( .125 )( 5 ) + (100- 3 - 5 -X)( .457 )
PROTEIN
CORN
Oats
SBM
12.8
= .075 X + .625
12.8
= .075 X + .625
12.8 - 42.044 - .625
= .075
-29.869
=
-.382 X
78.2
= X
13.8
=
92
( 5 )
+ ( 92 -X)( .457 )
+ 42.044 - .457 X
X - .457 X
( .125 ) =
STEP 2: (100 lbs) ( .128 ) = 12.8
12.8 - .625 = 12.175
STEP 3: 100- 5 - 3 = 92
(100-AMT Oats-AMT EMPTY)
12.175 / 92 = 13.2
- X
STEP 4:
---------- 32.5
:
:
: 13.2
:
:
:
45.7 ---------5.7
--------38.2
CORN = 78.2
Oats = 5
SBM = 13.8
7.5
MINERALS
--
.6 PERCENT CA
AND
.625
32.5
5.7
/
/
38.2
38.2
.5 PERCENT P
P IN GRAIN = (.0029)( 78.2 ) + (.0044)( 5 ) + (.006)( 13.8 ) =
CORN
Oats
SBM
.22678
+
.022
+
8.280002E-02
=
P STILL NEEDED = .5 - .33158 = .16842
AMT DICAL TO USE = .16842 / .185 = .9103783
CA IN GRAIN + DICAL = (.0002)( 78.2 ) + (.0010)( 5 ) + (.0025)( 13.8 ) + (.24)( .9103783 ) =
.01564
+
.005
+
3.450001E-02
+
.2184908
CA STILL NEEDED = .6 - .2736308 = .3263692
LIMESTONE TO USE TO GET .3263692 LBS CA = .3263692 / .38 =
TM Premix: 2 LBS/TON = 1 Lb/1000 = .5 lb/100 = .5%
Se Premix: 1 LB/TON = .5 lb/1000 = .05 lb/100 = .05%
Vit Premix: 6 LB/TON = 3 lb/1000 = .3 lb/100 = .3%
TYLAN-10: 80 g/ton = 40 g/1000 lb = 4 g/100 lb coming from
a compound with 10 g/lb of the tylan we want.
Therefore 4 g = X (10 g/lb) or 4/10 = .4 lbs TYLAN-10
CuSO4: 250 ppm = .025% Cu ; compound is 25% Cu so
.025 lb = X (.25) , or add .1 lb CuSO4 per 100 lbs feed.
OTHER should be calculated by subtracting all feeds from 100.0
.8588664
.2736308
.33158
x
x
92
92
=
=
78.2
13.8
12
ANSC 221
HOMEWORK 5
NAME -------------------------RATION BALANCING--SWINE TYPE
2 BASAL FEEDS AND MINERALS
---ANSWERS--FIXED AMOUNT OF Oats
BALANCE 100 POUNDS OF A RATION FOR SWINE TO CONTAIN
14.3 PERCENT PROTEIN.
MAKE THE RATION CONTAIN 19 PERCENT Oats AND USE CORN AND SOYBEAN MEAL TO SUPPLY
THE NEEDED AMOUNT OF ADDITIONAL PROTEIN.
LEAVE
3 PERCENT OF THE RATION FREE FOR VITAMINS, MINERALS, ETC.
BALANCE THE RATION TO CONTAIN .6 PERCENT CALCIUM AND .5 PERCENT PHOSPHORUS.
USE THE FOLLOWING INGREDIENT COMPOSITION (values are in percent)
Make it contain: 2 lbs/Ton of Trace Mineral premix
6 lbs/Ton of Vitamin premix
0.25% salt
250 PPM Copper from Copper Sulfate
1 lb per Ton of Selenium premix
80 Grams per Ton Tylosin
After balancing the ration, CALCULATE the percent LYSINE.
PROTEIN,
---------CORN
8.1
Oats
11.6
SOYBEAN MEAL
49.6
DICALCIUM PHOSPHATE
0
LIMESTONE
0
Tylan-10 contains 10 grams Tylosin/lb.
CuSO4-5H20 contains 25 percent copper.
PLACE YOUR ANSWERS HERE:
Percent
CORN
Oats
SOYBEAN MEAL
DICAL
LIMESTONE
SALT
TM Premix
Se PREMIX
VIT Premix
TYLAN-10
CU-SULFATE
OTHER
TOTAL
64.1
19
13.9
.7951891
.9015386
0.25
0.10
0.05
0.30
0.40
0.10
.1032723
------
100
PERCENT LYSINE IN RATION =
TON
1282
380
278
15.90378
18.03077
5
2
1
6
8
2
2.065446
-----2000
.7384601
CALCIUM,
---------.02
.10
.25
24.0
38
PHOSPHORUS,
---------.29
.44
.60
18.5
0
ANSWERS:
12
ANSC 221, Homework 5
ALGEBRAIC SOLUTION:
PEARSON SQUARE SOLUTION:
(100)( .143 ) = ( .081 )(X) + ( .116 )( 19 ) + (100- 3 - 19 -X)( .496 )
PROTEIN
CORN
Oats
SBM
14.3
= .081 X + 2.204
14.3
= .081 X + 2.204
14.3 - 38.688 - 2.204
= .081
-26.592
=
-.415 X
64.1
= X
13.9
=
78
( 19 )
+ ( 78 -X)( .496 )
+ 38.688 - .496 X
X - .496 X
( .116 ) =
STEP 2: (100 lbs) ( .143 ) = 14.3
14.3 - 2.204 = 12.096
STEP 3: 100- 19 - 3 = 78
12.096 / 78 =
- X
STEP 4:
---------- 34.1
:
:
: 15.5
:
:
:
49.6 ---------7.4
--------41.5
CORN = 64.1
Oats = 19
SBM = 13.9
8.1
MINERALS
--
.6 PERCENT CA
AND
2.204
(100-AMT Oats-AMT EMPTY)
15.5
34.1
7.4
/
/
41.5
41.5
.5 PERCENT P
P IN GRAIN = (.0029)( 64.1 ) + (.0044)( 19 ) + (.006)( 13.9 ) =
CORN
Oats
SBM
.18589
+
.0836
+
8.340001E-02
P STILL NEEDED = .5 - .35289 = .14711
AMT DICAL TO USE = .14711 / .185 = .7951891
CA IN GRAIN + DICAL = (.0002)( 64.1 ) + (.0010)( 19 ) + (.0025)( 13.9 ) + (.24)( .7951891 ) =
.01282
+
.019
+
.03475
+
.1908454
CA STILL NEEDED = .6 - .2574154 = .3425846
LIMESTONE TO USE TO GET .3425846 LBS CA = .3425846 / .38 =
TM Premix: 2 LBS/TON = 1 Lb/1000 = .5 lb/100 = .5%
Se Premix: 1 LB/TON = .5 lb/1000 = .05 lb/100 = .05%
Vit Premix: 6 LB/TON = 3 lb/1000 = .3 lb/100 = .3%
TYLAN-10: 80 g/ton = 40 g/1000 lb = 4 g/100 lb coming from
a compound with 10 g/lb of the tylan we want.
Therefore 4 g = X (10 g/lb) or 4/10 = .4 lbs TYLAN-10
CuSO4: 250 ppm = .025% Cu ; compound is 25% Cu so
.025 lb = X (.25) , or add .1 lb CuSO4 per 100 lbs feed.
OTHER should be calculated by subtracting all feeds from 100.0
.9015386
.2574154
=
.35289
x
x
78
78
=
=
64.1
13.9
13
ANSC 221
HOMEWORK 5
NAME -------------------------RATION BALANCING--SWINE TYPE
2 BASAL FEEDS AND MINERALS
---ANSWERS--FIXED AMOUNT OF Oats
BALANCE 100 POUNDS OF A RATION FOR SWINE TO CONTAIN
15.2 PERCENT PROTEIN.
MAKE THE RATION CONTAIN 14 PERCENT Oats AND USE CORN AND SOYBEAN MEAL TO SUPPLY
THE NEEDED AMOUNT OF ADDITIONAL PROTEIN.
LEAVE
3 PERCENT OF THE RATION FREE FOR VITAMINS, MINERALS, ETC.
BALANCE THE RATION TO CONTAIN .6 PERCENT CALCIUM AND .5 PERCENT PHOSPHORUS.
USE THE FOLLOWING INGREDIENT COMPOSITION (values are in percent)
Make it contain: 2 lbs/Ton of Trace Mineral premix
6 lbs/Ton of Vitamin premix
0.25% salt
250 PPM Copper from Copper Sulfate
1 lb per Ton of Selenium premix
80 Grams per Ton Tylosin
After balancing the ration, CALCULATE the percent LYSINE.
PROTEIN,
---------CORN
7.9
Oats
11.3
SOYBEAN MEAL
44.9
DICALCIUM PHOSPHATE
0
LIMESTONE
0
Tylan-10 contains 10 grams Tylosin/lb.
CuSO4-5H20 contains 25 percent copper.
PLACE YOUR ANSWERS HERE:
Percent
CORN
Oats
SOYBEAN MEAL
DICAL
LIMESTONE
SALT
TM Premix
Se PREMIX
VIT Premix
TYLAN-10
CU-SULFATE
OTHER
TOTAL
63.9
14
19.1
.7485947
.9100193
0.25
0.10
0.05
0.30
0.40
0.10
.141386
------
100
PERCENT LYSINE IN RATION =
TON
1278
280
382
14.97189
18.20039
5
2
1
6
8
2
2.827721
-----2000
.83924
CALCIUM,
---------.02
.10
.25
24.0
38
PHOSPHORUS,
---------.29
.44
.60
18.5
0
ANSWERS:
13
ANSC 221, Homework 5
ALGEBRAIC SOLUTION:
PEARSON SQUARE SOLUTION:
(100)( .152 ) = ( .079 )(X) + ( .113 )( 14 ) + (100- 3 - 14 -X)( .449 )
PROTEIN
CORN
Oats
SBM
15.2
= .079 X + 1.582
15.2
= .079 X + 1.582
15.2 - 37.267 - 1.582
= .079
-23.649
=
-.37 X
63.9
= X
19.1
MINERALS
=
--
83
+ ( 83 -X)( .449 )
+ 37.267 - .449 X
X - .449 X
( .113 ) =
STEP 3: 100- 14 - 3 = 83
(100-AMT Oats-AMT EMPTY)
13.618 / 83 = 16.4
STEP 4:
7.900001
---------- 28.5
:
:
: 16.4
:
:
:
44.9 ---------8.5
8.5
--------37
CORN = 63.9
Oats = 14
SBM = 19.1
AND
1.582
STEP 2: (100 lbs) ( .152 ) = 15.2
15.2 - 1.582 = 13.618
- X
.6 PERCENT CA
( 14 )
28.5
/
.5 PERCENT P
P IN GRAIN = (.0029)( 63.9 ) + (.0044)( 14 ) + (.006)( 19.1 ) =
CORN
Oats
SBM
.18531
+
.0616
+
.1146
=
.36151
P STILL NEEDED = .5 - .36151 = .13849
AMT DICAL TO USE = .13849 / .185 = .7485947
CA IN GRAIN + DICAL = (.0002)( 63.9 ) + (.0010)( 14 ) + (.0025)( 19.1 ) + (.24)( .7485947 ) =
.01278
+
.014
+
.04775
+
.1796627
CA STILL NEEDED = .6 - .2541927 = .3458073
LIMESTONE TO USE TO GET .3458073 LBS CA = .3458073 / .38 =
TM Premix: 2 LBS/TON = 1 Lb/1000 = .5 lb/100 = .5%
Se Premix: 1 LB/TON = .5 lb/1000 = .05 lb/100 = .05%
Vit Premix: 6 LB/TON = 3 lb/1000 = .3 lb/100 = .3%
TYLAN-10: 80 g/ton = 40 g/1000 lb = 4 g/100 lb coming from
a compound with 10 g/lb of the tylan we want.
Therefore 4 g = X (10 g/lb) or 4/10 = .4 lbs TYLAN-10
CuSO4: 250 ppm = .025% Cu ; compound is 25% Cu so
.025 lb = X (.25) , or add .1 lb CuSO4 per 100 lbs feed.
OTHER should be calculated by subtracting all feeds from 100.0
.9100193
.2541927
37
/
37
x
83
=
x
83
=
19.1
63.9
14
ANSC 221
HOMEWORK 5
NAME -------------------------RATION BALANCING--SWINE TYPE
2 BASAL FEEDS AND MINERALS
---ANSWERS--FIXED AMOUNT OF Oats
BALANCE 100 POUNDS OF A RATION FOR SWINE TO CONTAIN
15.2 PERCENT PROTEIN.
MAKE THE RATION CONTAIN 14 PERCENT Oats AND USE CORN AND SOYBEAN MEAL TO SUPPLY
THE NEEDED AMOUNT OF ADDITIONAL PROTEIN.
LEAVE
3 PERCENT OF THE RATION FREE FOR VITAMINS, MINERALS, ETC.
BALANCE THE RATION TO CONTAIN .6 PERCENT CALCIUM AND .5 PERCENT PHOSPHORUS.
USE THE FOLLOWING INGREDIENT COMPOSITION (values are in percent)
Make it contain: 2 lbs/Ton of Trace Mineral premix
6 lbs/Ton of Vitamin premix
0.25% salt
250 PPM Copper from Copper Sulfate
1 lb per Ton of Selenium premix
80 Grams per Ton Tylosin
After balancing the ration, CALCULATE the percent LYSINE.
PROTEIN,
---------CORN
8.1
Oats
12.4
SOYBEAN MEAL
45.9
DICALCIUM PHOSPHATE
0
LIMESTONE
0
Tylan-10 contains 10 grams Tylosin/lb.
CuSO4-5H20 contains 25 percent copper.
PLACE YOUR ANSWERS HERE:
Percent
CORN
Oats
SOYBEAN MEAL
DICAL
LIMESTONE
SALT
TM Premix
Se PREMIX
VIT Premix
TYLAN-10
CU-SULFATE
OTHER
TOTAL
65.2
14
17.8
.7703783
.9041296
0.25
0.10
0.05
0.30
0.40
0.10
.1254921
------
100
PERCENT LYSINE IN RATION =
TON
1304
280
356.0001
15.40757
18.08259
5
2
1
6
8
2
2.509842
-----2000
.8049201
CALCIUM,
---------.02
.10
.25
24.0
38
PHOSPHORUS,
---------.29
.44
.60
18.5
0
ANSWERS:
14
ANSC 221, Homework 5
ALGEBRAIC SOLUTION:
PEARSON SQUARE SOLUTION:
(100)( .152 ) = ( .081 )(X) + ( .124 )( 14 ) + (100- 3 - 14 -X)( .459 )
PROTEIN
CORN
Oats
SBM
15.2
= .081 X + 1.736
15.2
= .081 X + 1.736
15.2 - 38.097 - 1.736
= .081
-24.633
=
-.378 X
65.2
= X
17.8
=
83
( 14 )
+ ( 83 -X)( .459 )
+ 38.097 - .459 X
X - .459 X
( .124 ) =
STEP 2: (100 lbs) ( .152 ) = 15.2
15.2 - 1.736 = 13.464
STEP 3: 100- 14 - 3 = 83
13.464 / 83 =
- X
STEP 4:
---------- 29.7
:
:
: 16.2
:
:
:
45.9 ---------8.1
--------37.8
CORN = 65.2
Oats = 14
SBM = 17.8
8.1
MINERALS
--
.6 PERCENT CA
AND
1.736
(100-AMT Oats-AMT EMPTY)
16.2
29.7
8.1
/
.5 PERCENT P
P IN GRAIN = (.0029)( 65.2 ) + (.0044)( 14 ) + (.006)( 17.8 ) =
CORN
Oats
SBM
.18908
+
.0616
+
.1068
=
.35748
P STILL NEEDED = .5 - .35748 = .14252
AMT DICAL TO USE = .14252 / .185 = .7703783
CA IN GRAIN + DICAL = (.0002)( 65.2 ) + (.0010)( 14 ) + (.0025)( 17.8 ) + (.24)( .7703783 ) =
.01304
+
.014
+
4.450001E-02
+
.1848908
CA STILL NEEDED = .6 - .2564308 = .3435692
LIMESTONE TO USE TO GET .3435692 LBS CA = .3435692 / .38 =
TM Premix: 2 LBS/TON = 1 Lb/1000 = .5 lb/100 = .5%
Se Premix: 1 LB/TON = .5 lb/1000 = .05 lb/100 = .05%
Vit Premix: 6 LB/TON = 3 lb/1000 = .3 lb/100 = .3%
TYLAN-10: 80 g/ton = 40 g/1000 lb = 4 g/100 lb coming from
a compound with 10 g/lb of the tylan we want.
Therefore 4 g = X (10 g/lb) or 4/10 = .4 lbs TYLAN-10
CuSO4: 250 ppm = .025% Cu ; compound is 25% Cu so
.025 lb = X (.25) , or add .1 lb CuSO4 per 100 lbs feed.
OTHER should be calculated by subtracting all feeds from 100.0
.9041296
.2564308
/
37.8
37.8
x
x
83
83
=
=
65.2
17.8
15
ANSC 221
HOMEWORK 5
NAME -------------------------RATION BALANCING--SWINE TYPE
2 BASAL FEEDS AND MINERALS
---ANSWERS--FIXED AMOUNT OF Oats
BALANCE 100 POUNDS OF A RATION FOR SWINE TO CONTAIN
13.6 PERCENT PROTEIN.
MAKE THE RATION CONTAIN 11 PERCENT Oats AND USE CORN AND SOYBEAN MEAL TO SUPPLY
THE NEEDED AMOUNT OF ADDITIONAL PROTEIN.
LEAVE
3 PERCENT OF THE RATION FREE FOR VITAMINS, MINERALS, ETC.
BALANCE THE RATION TO CONTAIN .6 PERCENT CALCIUM AND .5 PERCENT PHOSPHORUS.
USE THE FOLLOWING INGREDIENT COMPOSITION (values are in percent)
Make it contain: 2 lbs/Ton of Trace Mineral premix
6 lbs/Ton of Vitamin premix
0.25% salt
250 PPM Copper from Copper Sulfate
1 lb per Ton of Selenium premix
80 Grams per Ton Tylosin
After balancing the ration, CALCULATE the percent LYSINE.
PROTEIN,
---------CORN
7.8
Oats
12.1
SOYBEAN MEAL
44.4
DICALCIUM PHOSPHATE
0
LIMESTONE
0
Tylan-10 contains 10 grams Tylosin/lb.
CuSO4-5H20 contains 25 percent copper.
PLACE YOUR ANSWERS HERE:
Percent
CORN
Oats
SOYBEAN MEAL
DICAL
LIMESTONE
SALT
TM Premix
Se PREMIX
VIT Premix
TYLAN-10
CU-SULFATE
OTHER
TOTAL
70.8
11
15.2
.8382704
.883303
0.25
0.10
0.05
0.30
0.40
0.10
.0784266
------
100
PERCENT LYSINE IN RATION =
TON
1416
220
303.9999
16.76541
17.66606
5
2
1
6
8
2
1.568532
-----2000
.7143799
CALCIUM,
---------.02
.10
.25
24.0
38
PHOSPHORUS,
---------.29
.44
.60
18.5
0
ANSWERS:
15
ANSC 221, Homework 5
ALGEBRAIC SOLUTION:
PEARSON SQUARE SOLUTION:
(100)( .136 ) = ( .078 )(X) + ( .121 )( 11 ) + (100- 3 - 11 -X)( .444 )
PROTEIN
CORN
Oats
SBM
13.6
= .078 X + 1.331
13.6
= .078 X + 1.331
13.6 - 38.184 - 1.331
= .078
-25.915
=
-.366 X
70.8
= X
15.2
=
86
( 11 )
+ ( 86 -X)( .444 )
+ 38.184 - .444 X
X - .444 X
( .121 ) =
STEP 2: (100 lbs) ( .136 ) = 13.6
13.6 - 1.331 = 12.269
STEP 3: 100- 11 - 3 = 86
12.269 / 86 =
- X
STEP 4:
---------- 30.1
:
:
: 14.3
:
:
:
44.4 ---------6.5
--------36.6
CORN = 70.8
Oats = 11
SBM = 15.2
7.8
MINERALS
--
.6 PERCENT CA
AND
1.331
(100-AMT Oats-AMT EMPTY)
14.3
30.1
6.5
/
/
36.6
36.6
.5 PERCENT P
P IN GRAIN = (.0029)( 70.8 ) + (.0044)( 11 ) + (.006)( 15.2 ) =
CORN
Oats
SBM
.20532
+
.0484
+
9.119998E-02
P STILL NEEDED = .5 - .34492 = .15508
AMT DICAL TO USE = .15508 / .185 = .8382704
CA IN GRAIN + DICAL = (.0002)( 70.8 ) + (.0010)( 11 ) + (.0025)( 15.2 ) + (.24)( .8382704 ) =
.01416
+
.011
+
3.799999E-02
+
.2011849
CA STILL NEEDED = .6 - .2643449 = .3356552
LIMESTONE TO USE TO GET .3356552 LBS CA = .3356552 / .38 =
TM Premix: 2 LBS/TON = 1 Lb/1000 = .5 lb/100 = .5%
Se Premix: 1 LB/TON = .5 lb/1000 = .05 lb/100 = .05%
Vit Premix: 6 LB/TON = 3 lb/1000 = .3 lb/100 = .3%
TYLAN-10: 80 g/ton = 40 g/1000 lb = 4 g/100 lb coming from
a compound with 10 g/lb of the tylan we want.
Therefore 4 g = X (10 g/lb) or 4/10 = .4 lbs TYLAN-10
CuSO4: 250 ppm = .025% Cu ; compound is 25% Cu so
.025 lb = X (.25) , or add .1 lb CuSO4 per 100 lbs feed.
OTHER should be calculated by subtracting all feeds from 100.0
.883303
.2643449
=
.34492
x
x
86
86
=
=
70.8
15.2
16
ANSC 221
HOMEWORK 5
NAME -------------------------RATION BALANCING--SWINE TYPE
2 BASAL FEEDS AND MINERALS
---ANSWERS--FIXED AMOUNT OF Oats
BALANCE 100 POUNDS OF A RATION FOR SWINE TO CONTAIN
19.2 PERCENT PROTEIN.
MAKE THE RATION CONTAIN 9 PERCENT Oats AND USE CORN AND SOYBEAN MEAL TO SUPPLY
THE NEEDED AMOUNT OF ADDITIONAL PROTEIN.
LEAVE
3 PERCENT OF THE RATION FREE FOR VITAMINS, MINERALS, ETC.
BALANCE THE RATION TO CONTAIN .6 PERCENT CALCIUM AND .5 PERCENT PHOSPHORUS.
USE THE FOLLOWING INGREDIENT COMPOSITION (values are in percent)
Make it contain: 2 lbs/Ton of Trace Mineral premix
6 lbs/Ton of Vitamin premix
0.25% salt
250 PPM Copper from Copper Sulfate
1 lb per Ton of Selenium premix
80 Grams per Ton Tylosin
After balancing the ration, CALCULATE the percent LYSINE.
PROTEIN,
---------CORN
7.9
Oats
12.5
SOYBEAN MEAL
46.2
DICALCIUM PHOSPHATE
0
LIMESTONE
0
Tylan-10 contains 10 grams Tylosin/lb.
CuSO4-5H20 contains 25 percent copper.
PLACE YOUR ANSWERS HERE:
Percent
CORN
Oats
SOYBEAN MEAL
DICAL
LIMESTONE
SALT
TM Premix
Se PREMIX
VIT Premix
TYLAN-10
CU-SULFATE
OTHER
TOTAL
59
9
29
.6232432
.9397938
0.25
0.10
0.05
0.30
0.40
0.10
.2369629
------
100
PERCENT LYSINE IN RATION =
TON
1180
180
580
12.46486
18.79588
5
2
1
6
8
2
4.739258
-----2000
1.0641
CALCIUM,
---------.02
.10
.25
24.0
38
PHOSPHORUS,
---------.29
.44
.60
18.5
0
ANSWERS:
16
ANSC 221, Homework 5
ALGEBRAIC SOLUTION:
PEARSON SQUARE SOLUTION:
(100)( .192 ) = ( .079 )(X) + ( .125 )( 9 ) + (100- 3 - 9 -X)( .462 )
PROTEIN
CORN
Oats
SBM
19.2
= .079 X + 1.125
19.2
= .079 X + 1.125
19.2 - 40.656 - 1.125
= .079
-22.581
=
-.383 X
59
= X
29
MINERALS
=
--
88
+ ( 88 -X)( .462 )
+ 40.656 - .462 X
X - .462 X
( .125 ) =
STEP 3: 100- 9 - 3
18.075 /
= 88
88 =
STEP 4:
7.900001
---------- 25.7
:
:
: 20.5
:
:
:
46.2 ---------12.6
--------38.3
CORN = 59
Oats = 9
SBM = 29
AND
.5 PERCENT P
P IN GRAIN = (.0029)( 59 ) + (.0044)( 9 ) + (.006)( 29 ) =
CORN
Oats
SBM
.1711
+
.0396
+
.174
=
.3847
P STILL NEEDED = .5 - .3847 = .1153
AMT DICAL TO USE = .1153 / .185 = .6232432
CA IN GRAIN + DICAL = (.0002)( 59 ) + (.0010)( 9 ) + (.0025)( 29 ) + (.24)( .6232432 ) =
.0118
+
9.000001E-03
+
.0725
+
.1495784
CA STILL NEEDED = .6 - .2428784 = .3571216
LIMESTONE TO USE TO GET .3571216 LBS CA = .3571216 / .38 =
TM Premix: 2 LBS/TON = 1 Lb/1000 = .5 lb/100 = .5%
Se Premix: 1 LB/TON = .5 lb/1000 = .05 lb/100 = .05%
Vit Premix: 6 LB/TON = 3 lb/1000 = .3 lb/100 = .3%
TYLAN-10: 80 g/ton = 40 g/1000 lb = 4 g/100 lb coming from
a compound with 10 g/lb of the tylan we want.
Therefore 4 g = X (10 g/lb) or 4/10 = .4 lbs TYLAN-10
CuSO4: 250 ppm = .025% Cu ; compound is 25% Cu so
.025 lb = X (.25) , or add .1 lb CuSO4 per 100 lbs feed.
OTHER should be calculated by subtracting all feeds from 100.0
1.125
STEP 2: (100 lbs) ( .192 ) = 19.2
19.2 - 1.125 = 18.075
- X
.6 PERCENT CA
( 9 )
.9397938
.2428784
(100-AMT Oats-AMT EMPTY)
20.5
25.7
12.6
/
/
38.3
38.3
x
x
88
88
=
=
29
59
17
ANSC 221
HOMEWORK 5
NAME -------------------------RATION BALANCING--SWINE TYPE
2 BASAL FEEDS AND MINERALS
---ANSWERS--FIXED AMOUNT OF Oats
BALANCE 100 POUNDS OF A RATION FOR SWINE TO CONTAIN
19.3 PERCENT PROTEIN.
MAKE THE RATION CONTAIN 6 PERCENT Oats AND USE CORN AND SOYBEAN MEAL TO SUPPLY
THE NEEDED AMOUNT OF ADDITIONAL PROTEIN.
LEAVE
3 PERCENT OF THE RATION FREE FOR VITAMINS, MINERALS, ETC.
BALANCE THE RATION TO CONTAIN .6 PERCENT CALCIUM AND .5 PERCENT PHOSPHORUS.
USE THE FOLLOWING INGREDIENT COMPOSITION (values are in percent)
Make it contain: 2 lbs/Ton of Trace Mineral premix
6 lbs/Ton of Vitamin premix
0.25% salt
250 PPM Copper from Copper Sulfate
1 lb per Ton of Selenium premix
80 Grams per Ton Tylosin
After balancing the ration, CALCULATE the percent LYSINE.
PROTEIN,
---------CORN
8.5
Oats
12.2
SOYBEAN MEAL
46.5
DICALCIUM PHOSPHATE
0
LIMESTONE
0
Tylan-10 contains 10 grams Tylosin/lb.
CuSO4-5H20 contains 25 percent copper.
PLACE YOUR ANSWERS HERE:
Percent
CORN
Oats
SOYBEAN MEAL
DICAL
LIMESTONE
SALT
TM Premix
Se PREMIX
VIT Premix
TYLAN-10
CU-SULFATE
OTHER
TOTAL
62.5
6
28.5
.6559459
.9284816
0.25
0.10
0.05
0.30
0.40
0.10
.2155724
------
100
PERCENT LYSINE IN RATION =
TON
1250
120
570
13.11892
18.56963
5
2
1
6
8
2
4.311447
-----2000
1.029
CALCIUM,
---------.02
.10
.25
24.0
38
PHOSPHORUS,
---------.29
.44
.60
18.5
0
ANSWERS:
17
ANSC 221, Homework 5
ALGEBRAIC SOLUTION:
PEARSON SQUARE SOLUTION:
(100)( .193 ) = ( .085 )(X) + ( .122 )( 6 ) + (100- 3 - 6 -X)( .465 )
PROTEIN
CORN
Oats
SBM
19.3
= .085 X
19.3
= .085 X
19.3 - 42.315 - .732
-23.747
=
-.38
62.5
= X
28.5
=
91
+
+
=
X
.732
.732
.085
( 6 )
+ ( 91 -X)( .465 )
+ 42.315 - .465 X
X - .465 X
( .122 ) =
.732
STEP 2: (100 lbs) ( .193 ) = 19.3
19.3 - .732 = 18.568
STEP 3: 100- 6 - 3
18.568
- X
=
/
91
91
=
(100-AMT Oats-AMT EMPTY)
20.4
STEP 4:
---------- 26.1
:
:
: 20.4
:
:
:
46.5 ---------11.9
--------38
CORN = 62.5
Oats = 6
SBM = 28.5
8.5
MINERALS
--
.6 PERCENT CA
AND
26.1
/
38
x
91
=
62.5
11.9
/
38
x
91
=
28.5
.5 PERCENT P
P IN GRAIN = (.0029)( 62.5 ) + (.0044)( 6 ) + (.006)( 28.5 ) =
CORN
Oats
SBM
.18125
+
.0264
+
.171
=
.37865
P STILL NEEDED = .5 - .37865 = .12135
AMT DICAL TO USE = .12135 / .185 = .6559459
CA IN GRAIN + DICAL = (.0002)( 62.5 ) + (.0010)( 6 ) + (.0025)( 28.5 ) + (.24)( .6559459 ) =
.0125
+
.006
+
.07125
+
.157427
CA STILL NEEDED = .6 - .247177 = .352823
LIMESTONE TO USE TO GET .352823 LBS CA = .352823 / .38 = .9284816
TM Premix: 2 LBS/TON = 1 Lb/1000 = .5 lb/100 = .5%
Se Premix: 1 LB/TON = .5 lb/1000 = .05 lb/100 = .05%
Vit Premix: 6 LB/TON = 3 lb/1000 = .3 lb/100 = .3%
TYLAN-10: 80 g/ton = 40 g/1000 lb = 4 g/100 lb coming from
a compound with 10 g/lb of the tylan we want.
Therefore 4 g = X (10 g/lb) or 4/10 = .4 lbs TYLAN-10
CuSO4: 250 ppm = .025% Cu ; compound is 25% Cu so
.025 lb = X (.25) , or add .1 lb CuSO4 per 100 lbs feed.
OTHER should be calculated by subtracting all feeds from 100.0
.247177
18
ANSC 221
HOMEWORK 5
NAME -------------------------RATION BALANCING--SWINE TYPE
2 BASAL FEEDS AND MINERALS
---ANSWERS--FIXED AMOUNT OF Oats
BALANCE 100 POUNDS OF A RATION FOR SWINE TO CONTAIN
16.4 PERCENT PROTEIN.
MAKE THE RATION CONTAIN 5 PERCENT Oats AND USE CORN AND SOYBEAN MEAL TO SUPPLY
THE NEEDED AMOUNT OF ADDITIONAL PROTEIN.
LEAVE
3 PERCENT OF THE RATION FREE FOR VITAMINS, MINERALS, ETC.
BALANCE THE RATION TO CONTAIN .6 PERCENT CALCIUM AND .5 PERCENT PHOSPHORUS.
USE THE FOLLOWING INGREDIENT COMPOSITION (values are in percent)
Make it contain: 2 lbs/Ton of Trace Mineral premix
6 lbs/Ton of Vitamin premix
0.25% salt
250 PPM Copper from Copper Sulfate
1 lb per Ton of Selenium premix
80 Grams per Ton Tylosin
After balancing the ration, CALCULATE the percent LYSINE.
PROTEIN,
---------CORN
8.6
Oats
12.8
SOYBEAN MEAL
49
DICALCIUM PHOSPHATE
0
LIMESTONE
0
Tylan-10 contains 10 grams Tylosin/lb.
CuSO4-5H20 contains 25 percent copper.
CALCIUM,
---------.02
.10
.25
24.0
38
PLACE YOUR ANSWERS HERE:
Percent
TON
CORN
Oats
SOYBEAN MEAL
DICAL
LIMESTONE
SALT
TM Premix
Se PREMIX
VIT Premix
TYLAN-10
CU-SULFATE
OTHER
TOTAL
72.6
1452
5
100
19.4
388
.8165404
16.33081
.8842378
17.68476
0.25
5
0.10
2
0.05
1
0.30
6
0.40
8
0.10
2
9.922171E-02
----------100
2000
PERCENT LYSINE IN RATION =
.78146
1.984434
PHOSPHORUS,
---------.29
.44
.60
18.5
0
ANSWERS:
18
ANSC 221, Homework 5
ALGEBRAIC SOLUTION:
PEARSON SQUARE SOLUTION:
(100)( .164 ) = ( .086 )(X) + ( .128 )( 5 ) + (100- 3 - 5 -X)( .49 )
PROTEIN
CORN
Oats
SBM
16.4
= .086 X + .64
+ ( 92 -X)( .49 )
16.4
= .086 X + .64 + 45.08 - .49 X
16.4 - 45.08 - .64
= .086 X - .49 X
-29.32
=
-.404 X
72.6
= X
19.4
=
92
( 5 )
- X
.6 PERCENT CA
AND
STEP 4:
---------- 31.9
:
:
: 17.1
:
:
:
---------8.5
--------40.4
CORN = 72.6
Oats = 5
SBM = 19.4
31.9
8.5
/
.5 PERCENT P
P IN GRAIN = (.0029)( 72.6 ) + (.0044)( 5 ) + (.006)( 19.4 ) =
CORN
Oats
SBM
.21054
+
.022
+
.1164
=
.34894
P STILL NEEDED = .5 - .34894 = .15106
AMT DICAL TO USE = .15106 / .185 = .8165404
CA IN GRAIN + DICAL = (.0002)( 72.6 ) + (.0010)( 5 ) + (.0025)( 19.4 ) + (.24)( .8165404 ) =
.01452
+
.005
+
.0485
+
.1959697
CA STILL NEEDED = .6 - .2639897 = .3360103
LIMESTONE TO USE TO GET .3360103 LBS CA = .3360103 / .38 =
TM Premix: 2 LBS/TON = 1 Lb/1000 = .5 lb/100 = .5%
Se Premix: 1 LB/TON = .5 lb/1000 = .05 lb/100 = .05%
Vit Premix: 6 LB/TON = 3 lb/1000 = .3 lb/100 = .3%
TYLAN-10: 80 g/ton = 40 g/1000 lb = 4 g/100 lb coming from
a compound with 10 g/lb of the tylan we want.
Therefore 4 g = X (10 g/lb) or 4/10 = .4 lbs TYLAN-10
CuSO4: 250 ppm = .025% Cu ; compound is 25% Cu so
.025 lb = X (.25) , or add .1 lb CuSO4 per 100 lbs feed.
OTHER should be calculated by subtracting all feeds from 100.0
16.4
STEP 3: 100- 5 - 3 = 92
(100-AMT Oats-AMT EMPTY)
15.76 / 92 = 17.1
49
--
.64
STEP 2: (100 lbs) ( .164 ) =
16.4 - .64 = 15.76
8.6
MINERALS
( .128 ) =
.8842378
.2639897
/
40.4
40.4
x
x
92
=
72.6
92
=
19.4
19
ANSC 221
HOMEWORK 5
NAME -------------------------RATION BALANCING--SWINE TYPE
2 BASAL FEEDS AND MINERALS
---ANSWERS--FIXED AMOUNT OF Oats
BALANCE 100 POUNDS OF A RATION FOR SWINE TO CONTAIN
16.3 PERCENT PROTEIN.
MAKE THE RATION CONTAIN 12 PERCENT Oats AND USE CORN AND SOYBEAN MEAL TO SUPPLY
THE NEEDED AMOUNT OF ADDITIONAL PROTEIN.
LEAVE
3 PERCENT OF THE RATION FREE FOR VITAMINS, MINERALS, ETC.
BALANCE THE RATION TO CONTAIN .6 PERCENT CALCIUM AND .5 PERCENT PHOSPHORUS.
USE THE FOLLOWING INGREDIENT COMPOSITION (values are in percent)
Make it contain: 2 lbs/Ton of Trace Mineral premix
6 lbs/Ton of Vitamin premix
0.25% salt
250 PPM Copper from Copper Sulfate
1 lb per Ton of Selenium premix
80 Grams per Ton Tylosin
After balancing the ration, CALCULATE the percent LYSINE.
PROTEIN,
---------CORN
9.0
Oats
11.8
SOYBEAN MEAL
48
DICALCIUM PHOSPHATE
0
LIMESTONE
0
Tylan-10 contains 10 grams Tylosin/lb.
CuSO4-5H20 contains 25 percent copper.
PLACE YOUR ANSWERS HERE:
Percent
CORN
Oats
SOYBEAN MEAL
DICAL
LIMESTONE
SALT
TM Premix
Se PREMIX
VIT Premix
TYLAN-10
CU-SULFATE
OTHER
TOTAL
66.5
12
18.5
.7748649
.9012696
0.25
0.10
0.05
0.30
0.40
0.10
.1238654
------
100
PERCENT LYSINE IN RATION =
TON
1330
240
370
15.4973
18.02539
5
2
1
6
8
2
2.477307
-----2000
.8088
CALCIUM,
---------.02
.10
.25
24.0
38
PHOSPHORUS,
---------.29
.44
.60
18.5
0
ANSWERS:
19
ANSC 221, Homework 5
ALGEBRAIC SOLUTION:
PEARSON SQUARE SOLUTION:
(100)( .163 ) = ( .09 )(X) + ( .118 )( 12 ) + (100- 3 - 12 -X)( .48 )
PROTEIN
CORN
Oats
SBM
16.3
16.3
16.3 - 40.8
-25.916
66.5
18.5
= .09 X + 1.416
+ ( 85 -X)( .48 )
= .09 X + 1.416 + 40.8 - .48 X
- 1.416
= .09 X - .48 X
=
-.39 X
= X
=
85
( 12 )
STEP 3: 100- 12 - 3 = 85
(100-AMT Oats-AMT EMPTY)
14.884 / 85 = 17.5
- X
48
--
.6 PERCENT CA
AND
1.416
STEP 2: (100 lbs) ( .163 ) = 16.3
16.3 - 1.416 = 14.884
9
MINERALS
( .118 ) =
STEP 4:
---------- 30.5
:
:
: 17.5
:
:
:
---------8.5
--------39
CORN = 66.5
Oats = 12
SBM = 18.5
30.5
8.5
/
.5 PERCENT P
P IN GRAIN = (.0029)( 66.5 ) + (.0044)( 12 ) + (.006)( 18.5 ) =
CORN
Oats
SBM
.19285
+
.0528
+
.111
=
.35665
P STILL NEEDED = .5 - .35665 = .14335
AMT DICAL TO USE = .14335 / .185 = .7748649
CA IN GRAIN + DICAL = (.0002)( 66.5 ) + (.0010)( 12 ) + (.0025)( 18.5 ) + (.24)( .7748649 ) =
.0133
+
.012
+
.04625
+
.1859676
CA STILL NEEDED = .6 - .2575176 = .3424824
LIMESTONE TO USE TO GET .3424824 LBS CA = .3424824 / .38 =
TM Premix: 2 LBS/TON = 1 Lb/1000 = .5 lb/100 = .5%
Se Premix: 1 LB/TON = .5 lb/1000 = .05 lb/100 = .05%
Vit Premix: 6 LB/TON = 3 lb/1000 = .3 lb/100 = .3%
TYLAN-10: 80 g/ton = 40 g/1000 lb = 4 g/100 lb coming from
a compound with 10 g/lb of the tylan we want.
Therefore 4 g = X (10 g/lb) or 4/10 = .4 lbs TYLAN-10
CuSO4: 250 ppm = .025% Cu ; compound is 25% Cu so
.025 lb = X (.25) , or add .1 lb CuSO4 per 100 lbs feed.
OTHER should be calculated by subtracting all feeds from 100.0
.9012696
.2575176
/
39
39
x
x
85
85
=
=
66.5
18.5
20
ANSC 221
HOMEWORK 5
NAME -------------------------RATION BALANCING--SWINE TYPE
2 BASAL FEEDS AND MINERALS
---ANSWERS--FIXED AMOUNT OF Oats
BALANCE 100 POUNDS OF A RATION FOR SWINE TO CONTAIN
16.1 PERCENT PROTEIN.
MAKE THE RATION CONTAIN 9 PERCENT Oats AND USE CORN AND SOYBEAN MEAL TO SUPPLY
THE NEEDED AMOUNT OF ADDITIONAL PROTEIN.
LEAVE
3 PERCENT OF THE RATION FREE FOR VITAMINS, MINERALS, ETC.
BALANCE THE RATION TO CONTAIN .6 PERCENT CALCIUM AND .5 PERCENT PHOSPHORUS.
USE THE FOLLOWING INGREDIENT COMPOSITION (values are in percent)
Make it contain: 2 lbs/Ton of Trace Mineral premix
6 lbs/Ton of Vitamin premix
0.25% salt
250 PPM Copper from Copper Sulfate
1 lb per Ton of Selenium premix
80 Grams per Ton Tylosin
After balancing the ration, CALCULATE the percent LYSINE.
PROTEIN,
---------CORN
8.1
Oats
11.7
SOYBEAN MEAL
46.4
DICALCIUM PHOSPHATE
0
LIMESTONE
0
Tylan-10 contains 10 grams Tylosin/lb.
CuSO4-5H20 contains 25 percent copper.
PLACE YOUR ANSWERS HERE:
Percent
CORN
Oats
SOYBEAN MEAL
DICAL
LIMESTONE
SALT
TM Premix
Se PREMIX
VIT Premix
TYLAN-10
CU-SULFATE
OTHER
TOTAL
67.3
9
20.7
.7623244
.90219
0.25
0.10
0.05
0.30
0.40
0.10
.1354856
------
100
PERCENT LYSINE IN RATION =
TON
1346
180
413.9999
15.24649
18.0438
5
2
1
6
8
2
2.709713
-----2000
.8449799
CALCIUM,
---------.02
.10
.25
24.0
38
PHOSPHORUS,
---------.29
.44
.60
18.5
0
ANSWERS:
20
ANSC 221, Homework 5
ALGEBRAIC SOLUTION:
PEARSON SQUARE SOLUTION:
(100)( .161 ) = ( .081 )(X) + ( .117 )( 9 ) + (100- 3 - 9 -X)( .464 )
PROTEIN
CORN
Oats
SBM
16.1
= .081 X + 1.053
16.1
= .081 X + 1.053
16.1 - 40.832 - 1.053
= .081
-25.785
=
-.383 X
67.3
= X
20.7
=
88
( 9 )
+ ( 88 -X)( .464 )
+ 40.832 - .464 X
X - .464 X
( .117 ) =
STEP 2: (100 lbs) ( .161 ) = 16.1
16.1 - 1.053 = 15.047
STEP 3: 100- 9 - 3 = 88
(100-AMT Oats-AMT EMPTY)
15.047 / 88 = 17.1
- X
STEP 4:
---------- 29.3
:
:
: 17.1
:
:
:
46.4 ---------9
--------38.3
CORN = 67.3
Oats = 9
SBM = 20.7
8.1
MINERALS
--
.6 PERCENT CA
AND
1.053
29.3
9
/
38.3
.5 PERCENT P
P IN GRAIN = (.0029)( 67.3 ) + (.0044)( 9 ) + (.006)( 20.7 ) =
CORN
Oats
SBM
.19517
+
.0396
+
.1242
=
.35897
P STILL NEEDED = .5 - .35897 = .14103
AMT DICAL TO USE = .14103 / .185 = .7623244
CA IN GRAIN + DICAL = (.0002)( 67.3 ) + (.0010)( 9 ) + (.0025)( 20.7 ) + (.24)( .7623244 ) = .2571678
.01346
+
9.000001E-03
+
5.174999E-02
+
.1829578
CA STILL NEEDED = .6 - .2571678 = .3428322
LIMESTONE TO USE TO GET .3428322 LBS CA = .3428322 / .38 =
TM Premix: 2 LBS/TON = 1 Lb/1000 = .5 lb/100 = .5%
Se Premix: 1 LB/TON = .5 lb/1000 = .05 lb/100 = .05%
Vit Premix: 6 LB/TON = 3 lb/1000 = .3 lb/100 = .3%
TYLAN-10: 80 g/ton = 40 g/1000 lb = 4 g/100 lb coming from
a compound with 10 g/lb of the tylan we want.
Therefore 4 g = X (10 g/lb) or 4/10 = .4 lbs TYLAN-10
CuSO4: 250 ppm = .025% Cu ; compound is 25% Cu so
.025 lb = X (.25) , or add .1 lb CuSO4 per 100 lbs feed.
OTHER should be calculated by subtracting all feeds from 100.0
.90219
/
38.3
x
88
x
=
88
=
20.7
67.3
21
ANSC 221
HOMEWORK 5
NAME -------------------------RATION BALANCING--SWINE TYPE
2 BASAL FEEDS AND MINERALS
---ANSWERS--FIXED AMOUNT OF Oats
BALANCE 100 POUNDS OF A RATION FOR SWINE TO CONTAIN
12.4 PERCENT PROTEIN.
MAKE THE RATION CONTAIN 10 PERCENT Oats AND USE CORN AND SOYBEAN MEAL TO SUPPLY
THE NEEDED AMOUNT OF ADDITIONAL PROTEIN.
LEAVE
3 PERCENT OF THE RATION FREE FOR VITAMINS, MINERALS, ETC.
BALANCE THE RATION TO CONTAIN .6 PERCENT CALCIUM AND .5 PERCENT PHOSPHORUS.
USE THE FOLLOWING INGREDIENT COMPOSITION (values are in percent)
Make it contain: 2 lbs/Ton of Trace Mineral premix
6 lbs/Ton of Vitamin premix
0.25% salt
250 PPM Copper from Copper Sulfate
1 lb per Ton of Selenium premix
80 Grams per Ton Tylosin
After balancing the ration, CALCULATE the percent LYSINE.
PROTEIN,
---------CORN
7.9
Oats
12.9
SOYBEAN MEAL
44.3
DICALCIUM PHOSPHATE
0
LIMESTONE
0
Tylan-10 contains 10 grams Tylosin/lb.
CuSO4-5H20 contains 25 percent copper.
CALCIUM,
---------.02
.10
.25
24.0
38
PLACE YOUR ANSWERS HERE:
Percent
TON
CORN
Oats
SOYBEAN MEAL
DICAL
LIMESTONE
SALT
TM Premix
Se PREMIX
VIT Premix
TYLAN-10
CU-SULFATE
OTHER
TOTAL
75.4
1508
10
200
11.6
232
.9067028
18.13406
.8639773
17.27955
0.25
5
0.10
2
0.05
1
0.30
6
0.40
8
0.10
2
2.931988E-02
----------100
2000
PERCENT LYSINE IN RATION =
.61204
.5863976
PHOSPHORUS,
---------.29
.44
.60
18.5
0
ANSWERS:
21
ANSC 221, Homework 5
ALGEBRAIC SOLUTION:
PEARSON SQUARE SOLUTION:
(100)( .124 ) = ( .079 )(X) + ( .129 )( 10 ) + (100- 3 - 10 -X)( .443 )
PROTEIN
CORN
Oats
SBM
12.4
= .079 X + 1.29
12.4
= .079 X + 1.29
12.4 - 38.541 - 1.29
= .079
-27.431
=
-.364 X
75.4
= X
11.6
=
87
( 10 )
+ ( 87 -X)( .443 )
+ 38.541 - .443 X
X - .443 X
( .129 ) =
1.29
STEP 2: (100 lbs) ( .124 ) = 12.4
12.4 - 1.29 = 11.11
- X
STEP 3: 100- 10 - 3
11.11 /
= 87
87 =
STEP 4:
7.900001
----------
31.5
(100-AMT Oats-AMT EMPTY)
12.8
31.5
/
36.4
x
87
=
=
11.6
75.4
:
:
: 12.8
:
:
:
44.3 ---------4.9
--------36.4
CORN = 75.4
Oats = 10
SBM = 11.6
MINERALS
--
.6 PERCENT CA
AND
4.9
/
36.4
.5 PERCENT P
P IN GRAIN = (.0029)( 75.4 ) + (.0044)( 10 ) + (.006)( 11.6 ) =
CORN
Oats
SBM
.21866
+
.044
+
6.959999E-02
=
P STILL NEEDED = .5 - .33226 = .16774
AMT DICAL TO USE = .16774 / .185 = .9067028
CA IN GRAIN + DICAL = (.0002)( 75.4 ) + (.0010)( 10 ) + (.0025)( 11.6 ) + (.24)( .9067028 ) =
.01508
+
.01
+
.029
+
.2176087
CA STILL NEEDED = .6 - .2716886 = .3283114
LIMESTONE TO USE TO GET .3283114 LBS CA = .3283114 / .38 =
TM Premix: 2 LBS/TON = 1 Lb/1000 = .5 lb/100 = .5%
Se Premix: 1 LB/TON = .5 lb/1000 = .05 lb/100 = .05%
Vit Premix: 6 LB/TON = 3 lb/1000 = .3 lb/100 = .3%
TYLAN-10: 80 g/ton = 40 g/1000 lb = 4 g/100 lb coming from
a compound with 10 g/lb of the tylan we want.
Therefore 4 g = X (10 g/lb) or 4/10 = .4 lbs TYLAN-10
CuSO4: 250 ppm = .025% Cu ; compound is 25% Cu so
.025 lb = X (.25) , or add .1 lb CuSO4 per 100 lbs feed.
OTHER should be calculated by subtracting all feeds from 100.0
.8639773
.2716886
.33226
x
87
22
ANSC 221
HOMEWORK 5
NAME -------------------------RATION BALANCING--SWINE TYPE
2 BASAL FEEDS AND MINERALS
---ANSWERS--FIXED AMOUNT OF Oats
BALANCE 100 POUNDS OF A RATION FOR SWINE TO CONTAIN
14.9 PERCENT PROTEIN.
MAKE THE RATION CONTAIN 8 PERCENT Oats AND USE CORN AND SOYBEAN MEAL TO SUPPLY
THE NEEDED AMOUNT OF ADDITIONAL PROTEIN.
LEAVE
3 PERCENT OF THE RATION FREE FOR VITAMINS, MINERALS, ETC.
BALANCE THE RATION TO CONTAIN .6 PERCENT CALCIUM AND .5 PERCENT PHOSPHORUS.
USE THE FOLLOWING INGREDIENT COMPOSITION (values are in percent)
Make it contain: 2 lbs/Ton of Trace Mineral premix
6 lbs/Ton of Vitamin premix
0.25% salt
250 PPM Copper from Copper Sulfate
1 lb per Ton of Selenium premix
80 Grams per Ton Tylosin
After balancing the ration, CALCULATE the percent LYSINE.
PROTEIN,
---------CORN
8.3
Oats
11.3
SOYBEAN MEAL
46.8
DICALCIUM PHOSPHATE
0
LIMESTONE
0
Tylan-10 contains 10 grams Tylosin/lb.
CuSO4-5H20 contains 25 percent copper.
CALCIUM,
---------.02
.10
.25
24.0
38
PLACE YOUR ANSWERS HERE:
Percent
TON
CORN
Oats
SOYBEAN MEAL
DICAL
LIMESTONE
SALT
TM Premix
Se PREMIX
VIT Premix
TYLAN-10
CU-SULFATE
OTHER
TOTAL
71.8
1436
8
160
17.2
343.9999
.8290811
16.58162
.8833173
17.66635
0.25
5
0.10
2
0.05
1
0.30
6
0.40
8
0.10
2
8.760154E-02
----------100
2000
PERCENT LYSINE IN RATION =
.7452799
1.752031
PHOSPHORUS,
---------.29
.44
.60
18.5
0
ANSWERS:
22
ANSC 221, Homework 5
ALGEBRAIC SOLUTION:
PEARSON SQUARE SOLUTION:
(100)( .149 ) = ( .083 )(X) + ( .113 )( 8 ) + (100- 3 - 8 -X)( .468 )
PROTEIN
CORN
Oats
SBM
14.9
= .083 X + .904
14.9
= .083 X + .904
14.9 - 41.652 - .904
= .083
-27.656
=
-.385 X
71.8
= X
17.2
=
89
( 8 )
+ ( 89 -X)( .468 )
+ 41.652 - .468 X
X - .468 X
( .113 ) =
STEP 2: (100 lbs) ( .149 ) = 14.9
14.9 - .904 = 13.996
STEP 3: 100- 8 - 3 = 89
(100-AMT Oats-AMT EMPTY)
13.996 / 89 = 15.7
- X
STEP 4:
---------- 31.1
:
:
: 15.7
:
:
:
46.8 ---------7.4
--------38.5
CORN = 71.8
Oats = 8
SBM = 17.2
8.3
MINERALS
--
.6 PERCENT CA
AND
.904
31.1
7.4
/
.5 PERCENT P
P IN GRAIN = (.0029)( 71.8 ) + (.0044)( 8 ) + (.006)( 17.2 ) =
CORN
Oats
SBM
.20822
+
.0352
+
.1032
=
.34662
P STILL NEEDED = .5 - .34662 = .15338
AMT DICAL TO USE = .15338 / .185 = .8290811
CA IN GRAIN + DICAL = (.0002)( 71.8 ) + (.0010)( 8 ) + (.0025)( 17.2 ) + (.24)( .8290811 ) =
.01436
+
.008
+
4.299999E-02
+
.1989795
CA STILL NEEDED = .6 - .2643394 = .3356606
LIMESTONE TO USE TO GET .3356606 LBS CA = .3356606 / .38 =
TM Premix: 2 LBS/TON = 1 Lb/1000 = .5 lb/100 = .5%
Se Premix: 1 LB/TON = .5 lb/1000 = .05 lb/100 = .05%
Vit Premix: 6 LB/TON = 3 lb/1000 = .3 lb/100 = .3%
TYLAN-10: 80 g/ton = 40 g/1000 lb = 4 g/100 lb coming from
a compound with 10 g/lb of the tylan we want.
Therefore 4 g = X (10 g/lb) or 4/10 = .4 lbs TYLAN-10
CuSO4: 250 ppm = .025% Cu ; compound is 25% Cu so
.025 lb = X (.25) , or add .1 lb CuSO4 per 100 lbs feed.
OTHER should be calculated by subtracting all feeds from 100.0
.8833173
.2643394
/
38.5
38.5
x
x
89
89
=
=
71.8
17.2
23
ANSC 221
HOMEWORK 5
NAME -------------------------RATION BALANCING--SWINE TYPE
2 BASAL FEEDS AND MINERALS
---ANSWERS--FIXED AMOUNT OF Oats
BALANCE 100 POUNDS OF A RATION FOR SWINE TO CONTAIN
17 PERCENT PROTEIN.
MAKE THE RATION CONTAIN 14 PERCENT Oats AND USE CORN AND SOYBEAN MEAL TO SUPPLY
THE NEEDED AMOUNT OF ADDITIONAL PROTEIN.
LEAVE
3 PERCENT OF THE RATION FREE FOR VITAMINS, MINERALS, ETC.
BALANCE THE RATION TO CONTAIN .6 PERCENT CALCIUM AND .5 PERCENT PHOSPHORUS.
USE THE FOLLOWING INGREDIENT COMPOSITION (values are in percent)
Make it contain: 2 lbs/Ton of Trace Mineral premix
6 lbs/Ton of Vitamin premix
0.25% salt
250 PPM Copper from Copper Sulfate
1 lb per Ton of Selenium premix
80 Grams per Ton Tylosin
After balancing the ration, CALCULATE the percent LYSINE.
PROTEIN,
---------CORN
8.3
Oats
11.3
SOYBEAN MEAL
49.6
DICALCIUM PHOSPHATE
0
LIMESTONE
0
Tylan-10 contains 10 grams Tylosin/lb.
CuSO4-5H20 contains 25 percent copper.
PLACE YOUR ANSWERS HERE:
Percent
CORN
Oats
SOYBEAN MEAL
DICAL
LIMESTONE
SALT
TM Premix
Se PREMIX
VIT Premix
TYLAN-10
CU-SULFATE
OTHER
TOTAL
62.3
14
20.7
.7217837
.9172683
0.25
0.10
0.05
0.30
0.40
0.10
.160948
------
100
PERCENT LYSINE IN RATION =
TON
1246
280
414
14.43567
18.34537
5
2
1
6
8
2
3.218961
-----2000
.88148
CALCIUM,
---------.02
.10
.25
24.0
38
PHOSPHORUS,
---------.29
.44
.60
18.5
0
ANSWERS:
23
ANSC 221, Homework 5
ALGEBRAIC SOLUTION:
PEARSON SQUARE SOLUTION:
(100)( .17 ) = ( .083 )(X) + ( .113 )( 14 ) + (100- 3 - 14 -X)( .496 )
PROTEIN
CORN
Oats
SBM
17
= .083 X + 1.582
17
= .083 X + 1.582
17 - 41.168 - 1.582
= .083
-25.75
=
-.413 X
62.3
= X
20.7
=
83
( 14 )
+ ( 83 -X)( .496 )
+ 41.168 - .496 X
X - .496 X
( .113 ) =
STEP 2: (100 lbs) ( .17 ) = 17
17 - 1.582 = 15.418
STEP 3: 100- 14 - 3 = 83
(100-AMT Oats-AMT EMPTY)
15.418 / 83 = 18.6
- X
STEP 4:
---------- 31
:
:
: 18.6
:
:
:
49.6 ---------10.3
--------41.3
CORN = 62.3
Oats = 14
SBM = 20.7
8.3
MINERALS
--
.6 PERCENT CA
AND
1.582
31
/
41.3
10.3
/
.5 PERCENT P
P IN GRAIN = (.0029)( 62.3 ) + (.0044)( 14 ) + (.006)( 20.7 ) =
CORN
Oats
SBM
.18067
+
.0616
+
.1242
=
.36647
P STILL NEEDED = .5 - .36647 = .13353
AMT DICAL TO USE = .13353 / .185 = .7217837
CA IN GRAIN + DICAL = (.0002)( 62.3 ) + (.0010)( 14 ) + (.0025)( 20.7 ) + (.24)( .7217837 ) =
.01246
+
.014
+
.05175
+
.1732281
CA STILL NEEDED = .6 - .2514381 = .3485619
LIMESTONE TO USE TO GET .3485619 LBS CA = .3485619 / .38 =
TM Premix: 2 LBS/TON = 1 Lb/1000 = .5 lb/100 = .5%
Se Premix: 1 LB/TON = .5 lb/1000 = .05 lb/100 = .05%
Vit Premix: 6 LB/TON = 3 lb/1000 = .3 lb/100 = .3%
TYLAN-10: 80 g/ton = 40 g/1000 lb = 4 g/100 lb coming from
a compound with 10 g/lb of the tylan we want.
Therefore 4 g = X (10 g/lb) or 4/10 = .4 lbs TYLAN-10
CuSO4: 250 ppm = .025% Cu ; compound is 25% Cu so
.025 lb = X (.25) , or add .1 lb CuSO4 per 100 lbs feed.
OTHER should be calculated by subtracting all feeds from 100.0
.9172683
.2514381
x
83
=
62.3
41.3
x
83
=
20.7
24
ANSC 221
HOMEWORK 5
NAME -------------------------RATION BALANCING--SWINE TYPE
2 BASAL FEEDS AND MINERALS
---ANSWERS--FIXED AMOUNT OF Oats
BALANCE 100 POUNDS OF A RATION FOR SWINE TO CONTAIN
16 PERCENT PROTEIN.
MAKE THE RATION CONTAIN 11 PERCENT Oats AND USE CORN AND SOYBEAN MEAL TO SUPPLY
THE NEEDED AMOUNT OF ADDITIONAL PROTEIN.
LEAVE
3 PERCENT OF THE RATION FREE FOR VITAMINS, MINERALS, ETC.
BALANCE THE RATION TO CONTAIN .6 PERCENT CALCIUM AND .5 PERCENT PHOSPHORUS.
USE THE FOLLOWING INGREDIENT COMPOSITION (values are in percent)
Make it contain: 2 lbs/Ton of Trace Mineral premix
6 lbs/Ton of Vitamin premix
0.25% salt
250 PPM Copper from Copper Sulfate
1 lb per Ton of Selenium premix
80 Grams per Ton Tylosin
After balancing the ration, CALCULATE the percent LYSINE.
PROTEIN,
---------CORN
8.1
Oats
11.2
SOYBEAN MEAL
48.7
DICALCIUM PHOSPHATE
0
LIMESTONE
0
Tylan-10 contains 10 grams Tylosin/lb.
CuSO4-5H20 contains 25 percent copper.
PLACE YOUR ANSWERS HERE:
Percent
CORN
Oats
SOYBEAN MEAL
DICAL
LIMESTONE
SALT
TM Premix
Se PREMIX
VIT Premix
TYLAN-10
CU-SULFATE
OTHER
TOTAL
66.8
11
19.2
.7712433
.9014254
0.25
0.10
0.05
0.30
0.40
0.10
.1273313
------
100
PERCENT LYSINE IN RATION =
TON
1336
220
383.9999
15.42487
18.02851
5
2
1
6
8
2
2.546625
-----2000
.81998
CALCIUM,
---------.02
.10
.25
24.0
38
PHOSPHORUS,
---------.29
.44
.60
18.5
0
ANSWERS:
24
ANSC 221, Homework 5
ALGEBRAIC SOLUTION:
PEARSON SQUARE SOLUTION:
(100)( .16 ) = ( .081 )(X) + ( .112 )( 11 ) + (100- 3 - 11 -X)( .487 )
PROTEIN
CORN
Oats
SBM
16
= .081 X + 1.232
16
= .081 X + 1.232
16 - 41.882 - 1.232
= .081
-27.114
=
-.406 X
66.8
= X
19.2
=
86
( 11 )
+ ( 86 -X)( .487 )
+ 41.882 - .487 X
X - .487 X
( .112 ) =
STEP 2: (100 lbs) ( .16 ) = 16
16 - 1.232 = 14.768
STEP 3: 100- 11 - 3 = 86
14.768 / 86 =
- X
STEP 4:
---------- 31.5
:
:
: 17.2
:
:
:
48.7 ---------9.1
--------40.6
CORN = 66.8
Oats = 11
SBM = 19.2
8.1
MINERALS
--
.6 PERCENT CA
AND
1.232
(100-AMT Oats-AMT EMPTY)
17.2
31.5
9.1
/
.5 PERCENT P
P IN GRAIN = (.0029)( 66.8 ) + (.0044)( 11 ) + (.006)( 19.2 ) =
CORN
Oats
SBM
.19372
+
.0484
+
.1152
=
.35732
P STILL NEEDED = .5 - .35732 = .14268
AMT DICAL TO USE = .14268 / .185 = .7712433
CA IN GRAIN + DICAL = (.0002)( 66.8 ) + (.0010)( 11 ) + (.0025)( 19.2 ) + (.24)( .7712433 ) =
.01336
+
.011
+
4.799999E-02
+
.1850984
CA STILL NEEDED = .6 - .2574584 = .3425416
LIMESTONE TO USE TO GET .3425416 LBS CA = .3425416 / .38 =
TM Premix: 2 LBS/TON = 1 Lb/1000 = .5 lb/100 = .5%
Se Premix: 1 LB/TON = .5 lb/1000 = .05 lb/100 = .05%
Vit Premix: 6 LB/TON = 3 lb/1000 = .3 lb/100 = .3%
TYLAN-10: 80 g/ton = 40 g/1000 lb = 4 g/100 lb coming from
a compound with 10 g/lb of the tylan we want.
Therefore 4 g = X (10 g/lb) or 4/10 = .4 lbs TYLAN-10
CuSO4: 250 ppm = .025% Cu ; compound is 25% Cu so
.025 lb = X (.25) , or add .1 lb CuSO4 per 100 lbs feed.
OTHER should be calculated by subtracting all feeds from 100.0
.9014254
.2574584
/
40.6
40.6
x
x
86
86
=
=
66.8
19.2
25
ANSC 221
HOMEWORK 5
NAME -------------------------RATION BALANCING--SWINE TYPE
2 BASAL FEEDS AND MINERALS
---ANSWERS--FIXED AMOUNT OF Oats
BALANCE 100 POUNDS OF A RATION FOR SWINE TO CONTAIN
18 PERCENT PROTEIN.
MAKE THE RATION CONTAIN 8 PERCENT Oats AND USE CORN AND SOYBEAN MEAL TO SUPPLY
THE NEEDED AMOUNT OF ADDITIONAL PROTEIN.
LEAVE
3 PERCENT OF THE RATION FREE FOR VITAMINS, MINERALS, ETC.
BALANCE THE RATION TO CONTAIN .6 PERCENT CALCIUM AND .5 PERCENT PHOSPHORUS.
USE THE FOLLOWING INGREDIENT COMPOSITION (values are in percent)
Make it contain: 2 lbs/Ton of Trace Mineral premix
6 lbs/Ton of Vitamin premix
0.25% salt
250 PPM Copper from Copper Sulfate
1 lb per Ton of Selenium premix
80 Grams per Ton Tylosin
After balancing the ration, CALCULATE the percent LYSINE.
PROTEIN,
---------CORN
8.5
Oats
12.6
SOYBEAN MEAL
44.1
DICALCIUM PHOSPHATE
0
LIMESTONE
0
Tylan-10 contains 10 grams Tylosin/lb.
CuSO4-5H20 contains 25 percent copper.
PLACE YOUR ANSWERS HERE:
Percent
CORN
Oats
SOYBEAN MEAL
DICAL
LIMESTONE
SALT
TM Premix
Se PREMIX
VIT Premix
TYLAN-10
CU-SULFATE
OTHER
TOTAL
62.5
8
26.5
.6732433
.9254517
0.25
0.10
0.05
0.30
0.40
0.10
.2013049
------
100
PERCENT LYSINE IN RATION =
TON
1250
160
530
13.46487
18.50903
5
2
1
6
8
2
4.026098
-----2000
.9908
CALCIUM,
---------.02
.10
.25
24.0
38
PHOSPHORUS,
---------.29
.44
.60
18.5
0
ANSWERS:
25
ANSC 221, Homework 5
ALGEBRAIC SOLUTION:
PEARSON SQUARE SOLUTION:
(100)( .18 ) = ( .085 )(X) + ( .126 )( 8 ) + (100- 3 - 8 -X)( .441 )
PROTEIN
CORN
Oats
SBM
18
= .085 X + 1.008
18
= .085 X + 1.008
18 - 39.249 - 1.008
= .085
-22.257
=
-.356 X
62.5
= X
26.5
=
89
( 8 )
+ ( 89 -X)( .441 )
+ 39.249 - .441 X
X - .441 X
( .126 ) =
STEP 2: (100 lbs) ( .18 ) = 18
18 - 1.008 = 16.992
STEP 3: 100- 8 - 3 = 89
(100-AMT Oats-AMT EMPTY)
16.992 / 89 = 19.1
- X
STEP 4:
---------- 25
:
:
: 19.1
:
:
:
44.1 ---------10.6
--------35.6
CORN = 62.5
Oats = 8
SBM = 26.5
8.5
MINERALS
--
.6 PERCENT CA
AND
1.008
25
/
35.6
10.6
/
.5 PERCENT P
P IN GRAIN = (.0029)( 62.5 ) + (.0044)( 8 ) + (.006)( 26.5 ) =
CORN
Oats
SBM
.18125
+
.0352
+
.159
=
.37545
P STILL NEEDED = .5 - .37545 = .12455
AMT DICAL TO USE = .12455 / .185 = .6732433
CA IN GRAIN + DICAL = (.0002)( 62.5 ) + (.0010)( 8 ) + (.0025)( 26.5 ) + (.24)( .6732433 ) =
.0125
+
.008
+
.06625
+
.1615784
CA STILL NEEDED = .6 - .2483284 = .3516716
LIMESTONE TO USE TO GET .3516716 LBS CA = .3516716 / .38 =
TM Premix: 2 LBS/TON = 1 Lb/1000 = .5 lb/100 = .5%
Se Premix: 1 LB/TON = .5 lb/1000 = .05 lb/100 = .05%
Vit Premix: 6 LB/TON = 3 lb/1000 = .3 lb/100 = .3%
TYLAN-10: 80 g/ton = 40 g/1000 lb = 4 g/100 lb coming from
a compound with 10 g/lb of the tylan we want.
Therefore 4 g = X (10 g/lb) or 4/10 = .4 lbs TYLAN-10
CuSO4: 250 ppm = .025% Cu ; compound is 25% Cu so
.025 lb = X (.25) , or add .1 lb CuSO4 per 100 lbs feed.
OTHER should be calculated by subtracting all feeds from 100.0
.9254517
.2483284
x
89
35.6
x
=
89
62.5
=
26.5
26
ANSC 221
HOMEWORK 5
NAME -------------------------RATION BALANCING--SWINE TYPE
2 BASAL FEEDS AND MINERALS
---ANSWERS--FIXED AMOUNT OF Oats
BALANCE 100 POUNDS OF A RATION FOR SWINE TO CONTAIN
12.5 PERCENT PROTEIN.
MAKE THE RATION CONTAIN 5 PERCENT Oats AND USE CORN AND SOYBEAN MEAL TO SUPPLY
THE NEEDED AMOUNT OF ADDITIONAL PROTEIN.
LEAVE
3 PERCENT OF THE RATION FREE FOR VITAMINS, MINERALS, ETC.
BALANCE THE RATION TO CONTAIN .6 PERCENT CALCIUM AND .5 PERCENT PHOSPHORUS.
USE THE FOLLOWING INGREDIENT COMPOSITION (values are in percent)
Make it contain: 2 lbs/Ton of Trace Mineral premix
6 lbs/Ton of Vitamin premix
0.25% salt
250 PPM Copper from Copper Sulfate
1 lb per Ton of Selenium premix
80 Grams per Ton Tylosin
After balancing the ration, CALCULATE the percent LYSINE.
PROTEIN,
---------CORN
7.5
Oats
11.6
SOYBEAN MEAL
44.7
DICALCIUM PHOSPHATE
0
LIMESTONE
0
Tylan-10 contains 10 grams Tylosin/lb.
CuSO4-5H20 contains 25 percent copper.
CALCIUM,
---------.02
.10
.25
24.0
38
PLACE YOUR ANSWERS HERE:
Percent
TON
CORN
Oats
SOYBEAN MEAL
DICAL
LIMESTONE
SALT
TM Premix
Se PREMIX
VIT Premix
TYLAN-10
CU-SULFATE
OTHER
TOTAL
78.5
1570
5
100
13.5
270
.9154054
18.30811
.8575072
17.15014
0.25
5
0.10
2
0.05
1
0.30
6
0.40
8
0.10
2
2.708745E-02
----------100
2000
PERCENT LYSINE IN RATION =
.6257
.541749
PHOSPHORUS,
---------.29
.44
.60
18.5
0
ANSWERS:
26
ANSC 221, Homework 5
ALGEBRAIC SOLUTION:
PEARSON SQUARE SOLUTION:
(100)( .125 ) = ( .075 )(X) + ( .116 )( 5 ) + (100- 3 - 5 -X)( .447 )
PROTEIN
CORN
Oats
SBM
12.5
= .075 X + .58
12.5
= .075 X + .58
12.5 - 41.124 - .58
= .075
-29.204
=
-.372 X
78.5
= X
13.5
=
92
( 5 )
+ ( 92 -X)( .447 )
+ 41.124 - .447 X
X - .447 X
( .116 ) =
STEP 2: (100 lbs) ( .125 ) =
12.5 - .58 = 11.92
STEP 3: 100- 5 - 3 = 92
11.92 / 92 =
- X
STEP 4:
---------- 31.7
:
:
: 13
:
:
:
44.7 ---------5.5
--------37.2
CORN = 78.5
Oats = 5
SBM = 13.5
7.5
MINERALS
--
.6 PERCENT CA
AND
.58
(100-AMT Oats-AMT EMPTY)
13
31.7
5.5
.5 PERCENT P
P IN GRAIN = (.0029)( 78.5 ) + (.0044)( 5 ) + (.006)( 13.5 ) =
CORN
Oats
SBM
.22765
+
.022
+
.081
=
.33065
P STILL NEEDED = .5 - .33065 = .16935
AMT DICAL TO USE = .16935 / .185 = .9154054
CA IN GRAIN + DICAL = (.0002)( 78.5 ) + (.0010)( 5 ) + (.0025)( 13.5 ) + (.24)( .9154054 ) =
.0157
+
.005
+
.03375
+
.2196973
CA STILL NEEDED = .6 - .2741473 = .3258527
LIMESTONE TO USE TO GET .3258527 LBS CA = .3258527 / .38 =
TM Premix: 2 LBS/TON = 1 Lb/1000 = .5 lb/100 = .5%
Se Premix: 1 LB/TON = .5 lb/1000 = .05 lb/100 = .05%
Vit Premix: 6 LB/TON = 3 lb/1000 = .3 lb/100 = .3%
TYLAN-10: 80 g/ton = 40 g/1000 lb = 4 g/100 lb coming from
a compound with 10 g/lb of the tylan we want.
Therefore 4 g = X (10 g/lb) or 4/10 = .4 lbs TYLAN-10
CuSO4: 250 ppm = .025% Cu ; compound is 25% Cu so
.025 lb = X (.25) , or add .1 lb CuSO4 per 100 lbs feed.
OTHER should be calculated by subtracting all feeds from 100.0
.8575072
12.5
.2741473
/
/
37.2
37.2
x
x
92
92
=
=
78.5
13.5
27
ANSC 221
HOMEWORK 5
NAME -------------------------RATION BALANCING--SWINE TYPE
2 BASAL FEEDS AND MINERALS
---ANSWERS--FIXED AMOUNT OF Oats
BALANCE 100 POUNDS OF A RATION FOR SWINE TO CONTAIN
16.2 PERCENT PROTEIN.
MAKE THE RATION CONTAIN 6 PERCENT Oats AND USE CORN AND SOYBEAN MEAL TO SUPPLY
THE NEEDED AMOUNT OF ADDITIONAL PROTEIN.
LEAVE
3 PERCENT OF THE RATION FREE FOR VITAMINS, MINERALS, ETC.
BALANCE THE RATION TO CONTAIN .6 PERCENT CALCIUM AND .5 PERCENT PHOSPHORUS.
USE THE FOLLOWING INGREDIENT COMPOSITION (values are in percent)
Make it contain: 2 lbs/Ton of Trace Mineral premix
6 lbs/Ton of Vitamin premix
0.25% salt
250 PPM Copper from Copper Sulfate
1 lb per Ton of Selenium premix
80 Grams per Ton Tylosin
After balancing the ration, CALCULATE the percent LYSINE.
PROTEIN,
---------CORN
8.6
Oats
12
SOYBEAN MEAL
48.9
DICALCIUM PHOSPHATE
0
LIMESTONE
0
Tylan-10 contains 10 grams Tylosin/lb.
CuSO4-5H20 contains 25 percent copper.
CALCIUM,
---------.02
.10
.25
24.0
38
PLACE YOUR ANSWERS HERE:
Percent
TON
CORN
Oats
SOYBEAN MEAL
DICAL
LIMESTONE
SALT
TM Premix
Se PREMIX
VIT Premix
TYLAN-10
CU-SULFATE
OTHER
TOTAL
72
1440
6
120
19
380
.8151351
16.3027
.8854411
17.70882
0.25
5
0.10
2
0.05
1
0.30
6
0.40
8
0.10
2
9.942377E-02
----------100
2000
PERCENT LYSINE IN RATION =
.7782
1.988475
PHOSPHORUS,
---------.29
.44
.60
18.5
0
ANSWERS:
27
ANSC 221, Homework 5
ALGEBRAIC SOLUTION:
PEARSON SQUARE SOLUTION:
(100)( .162 ) = ( .086 )(X) + ( .12 )( 6 ) + (100- 3 - 6 -X)( .489 )
PROTEIN
CORN
Oats
SBM
16.2
= .086 X + .72
16.2
= .086 X + .72
16.2 - 44.499 - .72
= .086
-29.019
=
-.403 X
72
= X
19
=
91
( 6 )
+ ( 91 -X)( .489 )
+ 44.499 - .489 X
X - .489 X
( .12 ) =
STEP 2: (100 lbs) ( .162 ) =
16.2 - .72 = 15.48
STEP 3: 100- 6 - 3 =
15.48 / 91
- X
--
.6 PERCENT CA
STEP 4:
---------- 31.9
:
:
: 17
:
:
:
48.9 ---------8.4
--------40.3
CORN = 72
Oats = 6
SBM = 19
AND
.5 PERCENT P
P IN GRAIN = (.0029)( 72 ) + (.0044)( 6 ) + (.006)( 19 ) =
CORN
Oats
SBM
.2088
+
.0264
+
.114
=
.3492
P STILL NEEDED = .5 - .3492 = .1508
AMT DICAL TO USE = .1508 / .185 = .8151351
CA IN GRAIN + DICAL = (.0002)( 72 ) + (.0010)( 6 ) + (.0025)( 19 ) + (.24)( .8151351 ) =
.0144
+
.006
+
.0475
+
.1956324
CA STILL NEEDED = .6 - .2635324 = .3364676
LIMESTONE TO USE TO GET .3364676 LBS CA = .3364676 / .38 =
TM Premix: 2 LBS/TON = 1 Lb/1000 = .5 lb/100 = .5%
Se Premix: 1 LB/TON = .5 lb/1000 = .05 lb/100 = .05%
Vit Premix: 6 LB/TON = 3 lb/1000 = .3 lb/100 = .3%
TYLAN-10: 80 g/ton = 40 g/1000 lb = 4 g/100 lb coming from
a compound with 10 g/lb of the tylan we want.
Therefore 4 g = X (10 g/lb) or 4/10 = .4 lbs TYLAN-10
CuSO4: 250 ppm = .025% Cu ; compound is 25% Cu so
.025 lb = X (.25) , or add .1 lb CuSO4 per 100 lbs feed.
OTHER should be calculated by subtracting all feeds from 100.0
.8854411
16.2
91
(100-AMT Oats-AMT EMPTY)
= 17
8.6
MINERALS
.72
.2635324
31.9
8.4
/
/
40.3
40.3
x
x
91
91
=
=
72
19
28
ANSC 221
HOMEWORK 5
NAME -------------------------RATION BALANCING--SWINE TYPE
2 BASAL FEEDS AND MINERALS
---ANSWERS--FIXED AMOUNT OF Oats
BALANCE 100 POUNDS OF A RATION FOR SWINE TO CONTAIN
13.5 PERCENT PROTEIN.
MAKE THE RATION CONTAIN 7 PERCENT Oats AND USE CORN AND SOYBEAN MEAL TO SUPPLY
THE NEEDED AMOUNT OF ADDITIONAL PROTEIN.
LEAVE
3 PERCENT OF THE RATION FREE FOR VITAMINS, MINERALS, ETC.
BALANCE THE RATION TO CONTAIN .6 PERCENT CALCIUM AND .5 PERCENT PHOSPHORUS.
USE THE FOLLOWING INGREDIENT COMPOSITION (values are in percent)
Make it contain: 2 lbs/Ton of Trace Mineral premix
6 lbs/Ton of Vitamin premix
0.25% salt
250 PPM Copper from Copper Sulfate
1 lb per Ton of Selenium premix
80 Grams per Ton Tylosin
After balancing the ration, CALCULATE the percent LYSINE.
PROTEIN,
---------CORN
8.6
Oats
11.9
SOYBEAN MEAL
46.1
DICALCIUM PHOSPHATE
0
LIMESTONE
0
Tylan-10 contains 10 grams Tylosin/lb.
CuSO4-5H20 contains 25 percent copper.
CALCIUM,
---------.02
.10
.25
24.0
38
PLACE YOUR ANSWERS HERE:
Percent
TON
CORN
Oats
SOYBEAN MEAL
DICAL
LIMESTONE
SALT
TM Premix
Se PREMIX
VIT Premix
TYLAN-10
CU-SULFATE
OTHER
TOTAL
76.9
1538
7
140
13.1
262
.9058918
18.11784
.8617263
17.23453
0.25
5
0.10
2
0.05
1
0.30
6
0.40
8
0.10
2
3.238177E-02
----------100
2000
PERCENT LYSINE IN RATION =
.62974
.6476355
PHOSPHORUS,
---------.29
.44
.60
18.5
0
ANSWERS:
28
ANSC 221, Homework 5
ALGEBRAIC SOLUTION:
PEARSON SQUARE SOLUTION:
(100)( .135 ) = ( .086 )(X) + ( .119 )( 7 ) + (100- 3 - 7 -X)( .461 )
PROTEIN
CORN
Oats
SBM
13.5
= .086 X + .8329999
+ ( 90 -X)( .461 )
13.5
= .086 X + .8329999 + 41.49 - .461 X
13.5 - 41.49 - .8329999
= .086 X - .461 X
-28.823
=
-.375 X
76.9
= X
13.1
=
90
( 7 )
( .119 ) =
STEP 2: (100 lbs) ( .135 ) = 13.5
13.5 - .8329999 = 12.667
STEP 3: 100- 7 - 3 = 90
(100-AMT Oats-AMT EMPTY)
12.667 / 90 = 14.1
- X
STEP 4:
---------- 32
:
:
: 14.1
:
:
:
46.1 ---------5.5
--------37.5
CORN = 76.9
Oats = 7
SBM = 13.1
8.6
MINERALS
--
.6 PERCENT CA
AND
.8329999
32
/
5.5
37.5
/
x
37.5
.5 PERCENT P
P IN GRAIN = (.0029)( 76.9 ) + (.0044)( 7 ) + (.006)( 13.1 ) =
CORN
Oats
SBM
.22301
+
.0308
+
7.859999E-02
P STILL NEEDED = .5 - .33241 = .16759
AMT DICAL TO USE = .16759 / .185 = .9058918
CA IN GRAIN + DICAL = (.0002)( 76.9 ) + (.0010)( 7 ) + (.0025)( 13.1 ) + (.24)( .9058918 ) =
.01538
+
.007
+
.03275
+
.217414
CA STILL NEEDED = .6 - .272544 = .327456
LIMESTONE TO USE TO GET .327456 LBS CA = .327456 / .38 = .8617263
TM Premix: 2 LBS/TON = 1 Lb/1000 = .5 lb/100 = .5%
Se Premix: 1 LB/TON = .5 lb/1000 = .05 lb/100 = .05%
Vit Premix: 6 LB/TON = 3 lb/1000 = .3 lb/100 = .3%
TYLAN-10: 80 g/ton = 40 g/1000 lb = 4 g/100 lb coming from
a compound with 10 g/lb of the tylan we want.
Therefore 4 g = X (10 g/lb) or 4/10 = .4 lbs TYLAN-10
CuSO4: 250 ppm = .025% Cu ; compound is 25% Cu so
.025 lb = X (.25) , or add .1 lb CuSO4 per 100 lbs feed.
OTHER should be calculated by subtracting all feeds from 100.0
.272544
=
.33241
90
x
=
90
76.9
=
13.1
29
ANSC 221
HOMEWORK 5
NAME -------------------------RATION BALANCING--SWINE TYPE
2 BASAL FEEDS AND MINERALS
---ANSWERS--FIXED AMOUNT OF Oats
BALANCE 100 POUNDS OF A RATION FOR SWINE TO CONTAIN
17.6 PERCENT PROTEIN.
MAKE THE RATION CONTAIN 16 PERCENT Oats AND USE CORN AND SOYBEAN MEAL TO SUPPLY
THE NEEDED AMOUNT OF ADDITIONAL PROTEIN.
LEAVE
3 PERCENT OF THE RATION FREE FOR VITAMINS, MINERALS, ETC.
BALANCE THE RATION TO CONTAIN .6 PERCENT CALCIUM AND .5 PERCENT PHOSPHORUS.
USE THE FOLLOWING INGREDIENT COMPOSITION (values are in percent)
Make it contain: 2 lbs/Ton of Trace Mineral premix
6 lbs/Ton of Vitamin premix
0.25% salt
250 PPM Copper from Copper Sulfate
1 lb per Ton of Selenium premix
80 Grams per Ton Tylosin
After balancing the ration, CALCULATE the percent LYSINE.
PROTEIN,
---------CORN
9.0
Oats
12
SOYBEAN MEAL
44.5
DICALCIUM PHOSPHATE
0
LIMESTONE
0
Tylan-10 contains 10 grams Tylosin/lb.
CuSO4-5H20 contains 25 percent copper.
PLACE YOUR ANSWERS HERE:
Percent
CORN
Oats
SOYBEAN MEAL
DICAL
LIMESTONE
SALT
TM Premix
Se PREMIX
VIT Premix
TYLAN-10
CU-SULFATE
OTHER
TOTAL
57.4
16
23.6
.656973
.9364383
0.25
0.10
0.05
0.30
0.40
0.10
.2065887
------
100
PERCENT LYSINE IN RATION =
TON
1148
320
472
13.13946
18.72877
5
2
1
6
8
2
4.131775
-----2000
.97264
CALCIUM,
---------.02
.10
.25
24.0
38
PHOSPHORUS,
---------.29
.44
.60
18.5
0
ANSWERS:
29
ANSC 221, Homework 5
ALGEBRAIC SOLUTION:
PEARSON SQUARE SOLUTION:
(100)( .176 ) = ( .09 )(X) + ( .12 )( 16 ) + (100- 3 - 16 -X)( .445 )
PROTEIN
CORN
Oats
SBM
17.6
= .09 X + 1.92
17.6
= .09 X + 1.92
17.6 - 36.045 - 1.92
= .09
-20.365
=
-.355 X
57.4
= X
23.6
=
81
( 16 )
+ ( 81 -X)( .445 )
+ 36.045 - .445 X
X - .445 X
( .12 ) =
STEP 2: (100 lbs) ( .176 ) = 17.6
17.6 - 1.92 = 15.68
STEP 3: 100- 16 - 3
15.68 /
- X
= 81
81 =
STEP 4:
---------- 25.1
:
:
: 19.4
:
:
:
44.5 ---------10.4
--------35.5
CORN = 57.4
Oats = 16
SBM = 23.6
9
MINERALS
--
.6 PERCENT CA
AND
1.92
(100-AMT Oats-AMT EMPTY)
19.4
25.1
/
10.4
.5 PERCENT P
P IN GRAIN = (.0029)( 57.4 ) + (.0044)( 16 ) + (.006)( 23.6 ) =
CORN
Oats
SBM
.16646
+
.0704
+
.1416
=
.37846
P STILL NEEDED = .5 - .37846 = .12154
AMT DICAL TO USE = .12154 / .185 = .656973
CA IN GRAIN + DICAL = (.0002)( 57.4 ) + (.0010)( 16 ) + (.0025)( 23.6 ) + (.24)( .656973 ) =
.01148
+
.016
+
.059
+
.1576735
CA STILL NEEDED = .6 - .2441535 = .3558465
LIMESTONE TO USE TO GET .3558465 LBS CA = .3558465 / .38 =
TM Premix: 2 LBS/TON = 1 Lb/1000 = .5 lb/100 = .5%
Se Premix: 1 LB/TON = .5 lb/1000 = .05 lb/100 = .05%
Vit Premix: 6 LB/TON = 3 lb/1000 = .3 lb/100 = .3%
TYLAN-10: 80 g/ton = 40 g/1000 lb = 4 g/100 lb coming from
a compound with 10 g/lb of the tylan we want.
Therefore 4 g = X (10 g/lb) or 4/10 = .4 lbs TYLAN-10
CuSO4: 250 ppm = .025% Cu ; compound is 25% Cu so
.025 lb = X (.25) , or add .1 lb CuSO4 per 100 lbs feed.
OTHER should be calculated by subtracting all feeds from 100.0
.9364383
.2441535
35.5
/
x
35.5
81
x
=
81
57.4
=
23.6
30
ANSC 221
HOMEWORK 5
NAME -------------------------RATION BALANCING--SWINE TYPE
2 BASAL FEEDS AND MINERALS
---ANSWERS--FIXED AMOUNT OF Oats
BALANCE 100 POUNDS OF A RATION FOR SWINE TO CONTAIN
15.2 PERCENT PROTEIN.
MAKE THE RATION CONTAIN 9 PERCENT Oats AND USE CORN AND SOYBEAN MEAL TO SUPPLY
THE NEEDED AMOUNT OF ADDITIONAL PROTEIN.
LEAVE
3 PERCENT OF THE RATION FREE FOR VITAMINS, MINERALS, ETC.
BALANCE THE RATION TO CONTAIN .6 PERCENT CALCIUM AND .5 PERCENT PHOSPHORUS.
USE THE FOLLOWING INGREDIENT COMPOSITION (values are in percent)
Make it contain: 2 lbs/Ton of Trace Mineral premix
6 lbs/Ton of Vitamin premix
0.25% salt
250 PPM Copper from Copper Sulfate
1 lb per Ton of Selenium premix
80 Grams per Ton Tylosin
After balancing the ration, CALCULATE the percent LYSINE.
PROTEIN,
---------CORN
8.1
Oats
11.9
SOYBEAN MEAL
45.2
DICALCIUM PHOSPHATE
0
LIMESTONE
0
Tylan-10 contains 10 grams Tylosin/lb.
CuSO4-5H20 contains 25 percent copper.
PLACE YOUR ANSWERS HERE:
Percent
CORN
Oats
SOYBEAN MEAL
DICAL
LIMESTONE
SALT
TM Premix
Se PREMIX
VIT Premix
TYLAN-10
CU-SULFATE
OTHER
TOTAL
69.1
9
18.9
.7924864
.8940349
0.25
0.10
0.05
0.30
0.40
0.10
.1134787
------
100
PERCENT LYSINE IN RATION =
TON
1382
180
378
15.84973
17.8807
5
2
1
6
8
2
2.269573
-----2000
.7974601
CALCIUM,
---------.02
.10
.25
24.0
38
PHOSPHORUS,
---------.29
.44
.60
18.5
0
ANSWERS:
30
ANSC 221, Homework 5
ALGEBRAIC SOLUTION:
PEARSON SQUARE SOLUTION:
(100)( .152 ) = ( .081 )(X) + ( .119 )( 9 ) + (100- 3 - 9 -X)( .452 )
PROTEIN
CORN
Oats
SBM
15.2
= .081 X + 1.071
15.2
= .081 X + 1.071
15.2 - 39.776 - 1.071
= .081
-25.647
=
-.371 X
69.1
= X
18.9
=
88
( 9 )
+ ( 88 -X)( .452 )
+ 39.776 - .452 X
X - .452 X
( .119 ) =
STEP 2: (100 lbs) ( .152 ) = 15.2
15.2 - 1.071 = 14.129
STEP 3: 100- 9 - 3 = 88
(100-AMT Oats-AMT EMPTY)
14.129 / 88 = 16.1
- X
STEP 4:
---------- 29.1
:
:
: 16.1
:
:
:
45.2 ---------8
--------37.1
CORN = 69.1
Oats = 9
SBM = 18.9
8.1
MINERALS
--
.6 PERCENT CA
AND
1.071
29.1
8
/
37.1
.5 PERCENT P
P IN GRAIN = (.0029)( 69.1 ) + (.0044)( 9 ) + (.006)( 18.9 ) =
CORN
Oats
SBM
.20039
+
.0396
+
.1134
=
.35339
P STILL NEEDED = .5 - .35339 = .14661
AMT DICAL TO USE = .14661 / .185 = .7924864
CA IN GRAIN + DICAL = (.0002)( 69.1 ) + (.0010)( 9 ) + (.0025)( 18.9 ) + (.24)( .7924864 ) =
.01382
+
9.000001E-03
+
.04725
+
.1901967
CA STILL NEEDED = .6 - .2602668 = .3397333
LIMESTONE TO USE TO GET .3397333 LBS CA = .3397333 / .38 =
TM Premix: 2 LBS/TON = 1 Lb/1000 = .5 lb/100 = .5%
Se Premix: 1 LB/TON = .5 lb/1000 = .05 lb/100 = .05%
Vit Premix: 6 LB/TON = 3 lb/1000 = .3 lb/100 = .3%
TYLAN-10: 80 g/ton = 40 g/1000 lb = 4 g/100 lb coming from
a compound with 10 g/lb of the tylan we want.
Therefore 4 g = X (10 g/lb) or 4/10 = .4 lbs TYLAN-10
CuSO4: 250 ppm = .025% Cu ; compound is 25% Cu so
.025 lb = X (.25) , or add .1 lb CuSO4 per 100 lbs feed.
OTHER should be calculated by subtracting all feeds from 100.0
.8940349
.2602668
/
37.1
x
88
x
=
88
=
18.9
69.1
31
ANSC 221
HOMEWORK 5
NAME -------------------------RATION BALANCING--SWINE TYPE
2 BASAL FEEDS AND MINERALS
---ANSWERS--FIXED AMOUNT OF Oats
BALANCE 100 POUNDS OF A RATION FOR SWINE TO CONTAIN
12.7 PERCENT PROTEIN.
MAKE THE RATION CONTAIN 6 PERCENT Oats AND USE CORN AND SOYBEAN MEAL TO SUPPLY
THE NEEDED AMOUNT OF ADDITIONAL PROTEIN.
LEAVE
3 PERCENT OF THE RATION FREE FOR VITAMINS, MINERALS, ETC.
BALANCE THE RATION TO CONTAIN .6 PERCENT CALCIUM AND .5 PERCENT PHOSPHORUS.
USE THE FOLLOWING INGREDIENT COMPOSITION (values are in percent)
Make it contain: 2 lbs/Ton of Trace Mineral premix
6 lbs/Ton of Vitamin premix
0.25% salt
250 PPM Copper from Copper Sulfate
1 lb per Ton of Selenium premix
80 Grams per Ton Tylosin
After balancing the ration, CALCULATE the percent LYSINE.
PROTEIN,
---------CORN
8.5
Oats
11.3
SOYBEAN MEAL
49.5
DICALCIUM PHOSPHATE
0
LIMESTONE
0
Tylan-10 contains 10 grams Tylosin/lb.
CuSO4-5H20 contains 25 percent copper.
PLACE YOUR ANSWERS HERE:
Percent
CORN
Oats
SOYBEAN MEAL
DICAL
LIMESTONE
SALT
TM Premix
Se PREMIX
VIT Premix
TYLAN-10
CU-SULFATE
OTHER
TOTAL
80.5
6
10.5
.9575676
.846931
0.25
0.10
0.05
0.30
0.40
0.10
-4.49872E-03
------
100
PERCENT LYSINE IN RATION =
TON
1610
120
210
19.15135
16.93862
5
2
1
6
8
2
-.0899744
-----2000
.5538
CALCIUM,
---------.02
.10
.25
24.0
38
PHOSPHORUS,
---------.29
.44
.60
18.5
0
ANSWERS:
31
ANSC 221, Homework 5
ALGEBRAIC SOLUTION:
PEARSON SQUARE SOLUTION:
(100)( .127 ) = ( .085 )(X) + ( .113 )( 6 ) + (100- 3 - 6 -X)( .495 )
PROTEIN
CORN
Oats
SBM
12.7
= .085 X
12.7
= .085 X
12.7 - 45.045 - .678
-33.023
=
-.41
80.5
= X
10.5
=
91
+
+
=
X
.678
.678
.085
( 6 )
+ ( 91 -X)( .495 )
+ 45.045 - .495 X
X - .495 X
( .113 ) =
STEP 2: (100 lbs) ( .127 ) = 12.7
12.7 - .678 = 12.022
STEP 3: 100- 6 - 3
12.022
- X
=
/
91
91
STEP 4:
---------- 36.3
:
:
: 13.2
:
:
:
49.5 ---------4.7
--------41
CORN = 80.5
Oats = 6
SBM = 10.5
8.5
MINERALS
--
.6 PERCENT CA
AND
.678
(100-AMT Oats-AMT EMPTY)
= 13.2
36.3
4.7
.5 PERCENT P
P IN GRAIN = (.0029)( 80.5 ) + (.0044)( 6 ) + (.006)( 10.5 ) =
CORN
Oats
SBM
.23345
+
.0264
+
.063
=
.32285
P STILL NEEDED = .5 - .32285 = .17715
AMT DICAL TO USE = .17715 / .185 = .9575676
CA IN GRAIN + DICAL = (.0002)( 80.5 ) + (.0010)( 6 ) + (.0025)( 10.5 ) + (.24)( .9575676 ) =
.0161
+
.006
+
.02625
+
.2298162
CA STILL NEEDED = .6 - .2781662 = .3218338
LIMESTONE TO USE TO GET .3218338 LBS CA = .3218338 / .38 =
TM Premix: 2 LBS/TON = 1 Lb/1000 = .5 lb/100 = .5%
Se Premix: 1 LB/TON = .5 lb/1000 = .05 lb/100 = .05%
Vit Premix: 6 LB/TON = 3 lb/1000 = .3 lb/100 = .3%
TYLAN-10: 80 g/ton = 40 g/1000 lb = 4 g/100 lb coming from
a compound with 10 g/lb of the tylan we want.
Therefore 4 g = X (10 g/lb) or 4/10 = .4 lbs TYLAN-10
CuSO4: 250 ppm = .025% Cu ; compound is 25% Cu so
.025 lb = X (.25) , or add .1 lb CuSO4 per 100 lbs feed.
OTHER should be calculated by subtracting all feeds from 100.0
.846931
.2781662
/
/
41
41
x
x
91
91
=
=
80.5
10.5
32
ANSC 221
HOMEWORK 5
NAME -------------------------RATION BALANCING--SWINE TYPE
2 BASAL FEEDS AND MINERALS
---ANSWERS--FIXED AMOUNT OF Oats
BALANCE 100 POUNDS OF A RATION FOR SWINE TO CONTAIN
15.5 PERCENT PROTEIN.
MAKE THE RATION CONTAIN 9 PERCENT Oats AND USE CORN AND SOYBEAN MEAL TO SUPPLY
THE NEEDED AMOUNT OF ADDITIONAL PROTEIN.
LEAVE
3 PERCENT OF THE RATION FREE FOR VITAMINS, MINERALS, ETC.
BALANCE THE RATION TO CONTAIN .6 PERCENT CALCIUM AND .5 PERCENT PHOSPHORUS.
USE THE FOLLOWING INGREDIENT COMPOSITION (values are in percent)
Make it contain: 2 lbs/Ton of Trace Mineral premix
6 lbs/Ton of Vitamin premix
0.25% salt
250 PPM Copper from Copper Sulfate
1 lb per Ton of Selenium premix
80 Grams per Ton Tylosin
After balancing the ration, CALCULATE the percent LYSINE.
PROTEIN,
---------CORN
7.9
Oats
12.7
SOYBEAN MEAL
48.5
DICALCIUM PHOSPHATE
0
LIMESTONE
0
Tylan-10 contains 10 grams Tylosin/lb.
CuSO4-5H20 contains 25 percent copper.
PLACE YOUR ANSWERS HERE:
Percent
CORN
Oats
SOYBEAN MEAL
DICAL
LIMESTONE
SALT
TM Premix
Se PREMIX
VIT Premix
TYLAN-10
CU-SULFATE
OTHER
TOTAL
69.8
9
18.2
.8042163
.8908635
0.25
0.10
0.05
0.30
0.40
0.10
.1049201
------
100
PERCENT LYSINE IN RATION =
TON
1396
180
363.9999
16.08433
17.81727
5
2
1
6
8
2
2.098403
-----2000
.77898
CALCIUM,
---------.02
.10
.25
24.0
38
PHOSPHORUS,
---------.29
.44
.60
18.5
0
ANSWERS:
32
ANSC 221, Homework 5
ALGEBRAIC SOLUTION:
PEARSON SQUARE SOLUTION:
(100)( .155 ) = ( .079 )(X) + ( .127 )( 9 ) + (100- 3 - 9 -X)( .485 )
PROTEIN
CORN
Oats
SBM
( 9 )
15.5
= .079 X + 1.143
+ ( 88 -X)( .485 )
15.5
= .079 X + 1.143 + 42.68 - .485 X
15.5 - 42.68 - 1.143
= .079 X - .485 X
-28.323
=
-.406 X
69.8
= X
18.2
=
88
( .127 ) =
1.143
STEP 2: (100 lbs) ( .155 ) = 15.5
15.5 - 1.143 = 14.357
STEP 3: 100- 9 - 3 = 88
(100-AMT Oats-AMT EMPTY)
14.357 / 88 = 16.3
- X
STEP 4:
7.900001
----------
32.2
32.2
/
40.6
x
88
=
=
18.2
69.8
:
:
: 16.3
:
:
:
48.5 ---------8.4
--------40.6
CORN = 69.8
Oats = 9
SBM = 18.2
MINERALS
--
.6 PERCENT CA
AND
8.4
/
.5 PERCENT P
P IN GRAIN = (.0029)( 69.8 ) + (.0044)( 9 ) + (.006)( 18.2 ) =
CORN
Oats
SBM
.20242
+
.0396
+
.1092
=
.35122
P STILL NEEDED = .5 - .35122 = .14878
AMT DICAL TO USE = .14878 / .185 = .8042163
CA IN GRAIN + DICAL = (.0002)( 69.8 ) + (.0010)( 9 ) + (.0025)( 18.2 ) + (.24)( .8042163 ) = .2614719
.01396
+
9.000001E-03
+
4.549999E-02
+
.1930119
CA STILL NEEDED = .6 - .2614719 = .3385281
LIMESTONE TO USE TO GET .3385281 LBS CA = .3385281 / .38 =
TM Premix: 2 LBS/TON = 1 Lb/1000 = .5 lb/100 = .5%
Se Premix: 1 LB/TON = .5 lb/1000 = .05 lb/100 = .05%
Vit Premix: 6 LB/TON = 3 lb/1000 = .3 lb/100 = .3%
TYLAN-10: 80 g/ton = 40 g/1000 lb = 4 g/100 lb coming from
a compound with 10 g/lb of the tylan we want.
Therefore 4 g = X (10 g/lb) or 4/10 = .4 lbs TYLAN-10
CuSO4: 250 ppm = .025% Cu ; compound is 25% Cu so
.025 lb = X (.25) , or add .1 lb CuSO4 per 100 lbs feed.
OTHER should be calculated by subtracting all feeds from 100.0
.8908635
40.6
x
88