Structure and Operation of
a Hydraulic Press
Made by Jardan Alexei
Initial inf:
Solution:
the whole building weighs = 5 500
tons(in newtons are 53 955 000 H),
but we'll get a little more 5 600 tons
in newtons are 54 936 000 H ('cause
we should be on the safe side)
F2 = F/(sum of H. press)
F2 = 54 936 000 H / 44 = 1 248 545,45 H , but
we'll get 1 275 000 H/ 129 969 kg ('cause we should be
on the safe side)
S1<S2 that's really important
We need to find out F1
S1 = п * 0,5^2 = 0,7
S2 = п * 2,4^2 = 18,09
I'll use that formal F2 = (F1 * S2) / S1 where F1
is unknown one
1 275 000 H = (F1 * 18,09) / 0,7 and that equal
50 000(F1) (5 100kg) and 'cause we're getting more for
safety
and if I want to raise this building only at 1
m(l2) we need l1 = 26 m but I think more rational will
be to raise it at height of 0,1 m(l2) and then we need
only 2,6m but for safety we shood get 2,7m
length = 80,92 m
weight = 17,92 m
height = 16 m
H. press for length = 16x2
H. press for wight = +5x2
sum of H. press = 44
l2 = m
D2 = 2,4 m
D1 = 0,5 m
and we end up with l2 = 0,1m and l1 = 2,6m
71 428,57 pascal
Structure and Operation of
a Hydraulic Press
Thank you for attention!!!
Made by Jardan Alexei