282215597
5/28/2016
1/1
Standard Deviation of F({f})
Assume that there is a set {f1,…,fN}I of values and a set of rules for using this set of values to produce a value F({f} I). If F
can be differentiated with respect to fi, the difference between F for the {f} I and that for the {f}J is given by
F f I F f J
N
i 1
F
fi , I fi , J
fi
(1.1)
The difference squared is
FI
FJ
2
F F
i 1, j 1 f i 0 f j
j 0
i
N
f
i,I
fi , J f j , I f j , J
(1.2)
The standard deviation in F is the limit that MI and MJ → infinity in
2
F ,M I ,M J
M I ,M J
1 N
1
F F
2 i 1 M I M J 1 I 1 fi f j
j 1
f
i,I
fi , J f j , I f j , J (1.3)
J 1
J I
If fi and fj are statistically independent, the terms with i ≠ j average to zero so that
F2 , M
M I ,M J
F
2
1
f
f
i,I i, J
i 1 f i 2 M I M J 1 I 1
J 1
J I
2
N
I
,M J
(1.4)
The term in parenthesis in the limit that MI and MJ become infinite is the standard deviation of the values of fi
M I ,M J
2
1
fi , I fi , J
2M I M J 1 I 1
2
i
(1.5)
J 1
J I
Finally the standard deviation in F is
2
F 2
i
i 1 f i
N
2
F
(1.6)
The relationship of to the standard deviation in fi for a Gaussian distribution is derived in Deviations.docx. In the case of Poisson
data with more than just a few counts i2=fi. The critical step is the assumption in going from (1.3) to (1.4) that the terms for i≠j sum
to zero.